What will be the output of the C#.NET code snippet given below?

byte b1 = 0xF7;
byte b2 = 0xAB;
byte temp;
temp = (byte)(b1 & b2);
Console.Write (temp + " ");
temp = (byte)(b1^b2);
Console.WriteLine(temp);

if ((n&16) == 16)
Console.WriteLine("Fourth bit is ON");

if ((n&8) == 8)
Console.WriteLine("Fourth bit is ON");

if ((n ! 8) == 8)
Console.WriteLine("Fourth bit is ON");

if ((n ^ 8) == 8)
Console.WriteLine("Fourth bit is ON");

if ((n ~ 8) == 8)
Console. WriteLine("Fourth bit is ON");

1. ++a++;
2. a += 1;
3. a ++ 1;
4. a = a +1;
5. a = +1;

1. &&
2. ||
3. !
4. Xor
5. %

int a = 10; 
int b = 20;
bool c;
c = !(a > b);

1. There is no error in the code snippet.
2. An error will be reported since ! can work only with an int.
3. A value 1 will be assigned to c.
4. A value True will be assigned to c.
5. A value False will be assigned to c.

1. The & operator can be used to Invert a bit.
2. The & operator can be used to put ON a bit.
3. The & operator can be used to put OFF a bit.
4. The & operator can be used to check whether a bit is ON.
5. The & operator can be used to check whether a bit is OFF.

byte b1 = 0xAB;
byte b2 = 0x99;
byte temp;
temp = (byte)~b2;
Console.Write(temp + " ");
temp = (byte)(b1 << b2);
Console.Write (temp + " ");
temp = (byte) (b2 >> 2);
Console.WriteLine(temp);

int d; 
d = Convert.ToInt32( !(30 < 20) );