C#.NET — Jagged array bounds: evaluate GetUpperBound on the second inner array. Code: int[][] a = new int[2][]; a[0] = new int[4]{6, 1, 4, 3}; a[1] = new int[3]{9, 2, 7}; Console.WriteLine(a[1].GetUpperBound(0));

Introduction / Context:
This tests your knowledge of array indexing and the GetUpperBound method. In a 1-D array of length N, valid indices are 0..N-1, and GetUpperBound(0) returns N-1.

Given Data / Assumptions:

• a[1] is a 1-D int[] with 3 elements: {9, 2, 7}.
• We ask for the upper bound of dimension 0.

Concept / Approach:
For any 1-D array arr of length L, arr.GetUpperBound(0) equals L - 1. Here L = 3, so the highest valid index is 2. Values like 3, 4, 7, or 9 are element values or lengths, not the upper index bound.

Step-by-Step Solution:

Verification / Alternative check:
Printing a[1].Length yields 3; confirming upper bound must be 2.

Why Other Options Are Wrong:
They confuse value, length, or an off-by-one index with the correct upper bound.

Common Pitfalls:
Off-by-one errors when thinking about 0-based indexing.

Final Answer:
2