C#.NET — Predict output with overload resolution and double formatting. Consider: namespace CuriousTabConsoleApplication { class SampleProgram { static void Main(string[] args) { int i = 10; double d = 34.340; fun(i); fun(d); } static void fun(double d) { Console.WriteLine(d + " "); } } } What will be printed?

Introduction / Context:
This program tests overload resolution (int to double conversion) and how doubles are formatted when concatenated with a string in Console.WriteLine.

Given Data / Assumptions:

• Only one overload exists: fun(double d).
• Main calls fun(i) where i is int and fun(d) where d is double.
• The method writes Console.WriteLine(d + " ").

Concept / Approach:
An int is implicitly converted to double to match the fun(double) signature. In the expression d + " ", the double is converted to its default string representation (culture-dependent general format “G”), then concatenated with a single trailing space, and finally written with a newline by WriteLine.

Step-by-Step Solution:

Verification / Alternative check:
Replacing WriteLine(d + " ") with WriteLine("{0} ", d) yields the same text. Using ToString("F6") would produce six fixed decimals (not used here).

Why Other Options Are Wrong:

• A shows six fixed decimals — not used here.
• B drops the fractional part of 34.340.
• C keeps three decimals including a trailing zero — not default formatting here.
• E is blank and not applicable.

Common Pitfalls:
Expecting WriteLine to preserve trailing zeros without an explicit format string; confusing numeric formatting with basic concatenation behavior.

Final Answer:
10 34.34