What will be the output of the program? #include int main() { const c = -11; const int d = 34; printf("%d, %d\n", c, d); return 0; }

Correct Answer: -11, 34

Explanation:

Step 1: const c = -11; The constant variable 'c' is declared and initialized to value "-11".

Step 2: const int d = 34; The constant variable 'd' is declared as an integer and initialized to value '34'.

Step 3: printf("%d, %d\n", c, d); The value of the variable 'c' and 'd' are printed.

Hence the output of the program is -11, 34

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