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- Question
A 470 Ω resistor and a coil with 125 Ω inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor is
Options- A. 152 mA
- B. 32 mA
- C. 12 mA
- D. 120 mA
- Correct Answer
- 120 mA
- 1. A 470 Ω resistor and a 200 mH coil are in parallel. Both components are across a 1.5 kHz ac source. The total admittance of the circuit, in polar form, is
Options- A. 12.60 ∠?76° mS
- B. 12.18∠76° mS
- C. 218 ∠?76° mS
- D. 12.18 ∠?76° mS Discuss
- 2. When the frequency of the voltage applied to a series RL circuit is increased, the phase angle
Options- A. decreases
- B. increases
- C. does not change
- D. cannot be determined without values Discuss
- 3. A 1.2 kΩ resistor is in series with a 15 mH coil across a 10 kHz ac source. The magnitude of the total impedance is
Options- A. 152.6 Ω
- B. 1,526 Ω
- C. 1,200 Ω
- D. 942 Ω Discuss
- 4. A 3.3 kΩ resistor and a 120 mH coil are in parallel. Both components are across a 2 kHz, 12 V ac source. The total current in the circuit is
Options- A. 8.74 mA
- B. 874 mA
- C. 874 µA
- D. 8.74 µA Discuss
- 5. A 47 Ω resistor is in series with an inductive reactance of 120 Ω across an ac source. The impedance, expressed in polar form, is
Options- A. 47∠68.6° Ω
- B. 120∠68.6° Ω
- C. 129∠31.4° Ω
- D. 129∠68.6° Ω Discuss
- 6. In a series RL circuit, 12 V rms is measured across the resistor, and 14 V rms is measured across the inductor. The peak value of the source voltage is
Options- A. 18.4 V
- B. 26.0 V
- C. 2 V
- D. 20 V Discuss
- 7. When the resistor voltage in a series RL circuit becomes less than the inductor voltage, the phase angle
Options- A. increases
- B. decreases
- C. is not affected
- D. cannot be determined Discuss
- 8. Vout = 500 mV, and Vin = 1.3 V. The ratio Vout/ Vin expressed in dB is
Options- A. 0 dB
- B. 8.30 dB
- C. ?8.30 dB
- D. 0.8 dB Discuss
- 9. The same signal in Problem 2 is applied to an RC high-pass filter. If the reactance is zero at the input frequency, the output voltage is
Options- A. 18 V peak-to-peak
- B. zero
- C. 9 V peak-to-peak
- D. 12.73 V peak-to-peak Discuss
- 10. In a series resonant band-pass filter, a lower value of Q results in
Options- A. a higher resonant frequency
- B. a smaller bandwidth
- C. a higher impedance
- D. a larger bandwidth Discuss
RL Circuits problems
Search Results
Correct Answer: 12.18 ∠?76° mS
Correct Answer: increases
Correct Answer: 1,526 Ω
Correct Answer: 8.74 mA
Correct Answer: 129∠68.6° Ω
Correct Answer: 26.0 V
Correct Answer: increases
Correct Answer: ?8.30 dB
Correct Answer: 18 V peak-to-peak
Correct Answer: a larger bandwidth
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