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- Question
A three-phase generator is connected to three 90 Ω load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?
Options- A. 0 A
- B. 1.33 A
- C. 3.99 A
- D. 2.66 A
- Correct Answer
- 0 A
- 1. If 24 V are applied across a resistor and there are 10.9 mA of current, the resistance is
Options- A. 220 kΩ
- B. 22 kΩ
- C. 2.2 kΩ
- D. 220 Ω Discuss
- 2. When there is 12 mA of current through a 1.2 kΩ resistor, the voltage across the resistor is
Options- A. 14.4 V
- B. 1.4 V
- C. 100 V
- D. 10 V Discuss
- 3. A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3∠0° mA. The source voltage, expressed in polar form, is
Options- A. 3.84∠20.6° V
- B. 12.8∠20.6° V
- C. 0.3∠20.6° V
- D. 13.84∠69.4° V Discuss
- 4. A coil of wire is placed in a changing magnetic field. If the number of turns in the coil is decreased, the voltage induced across the coil will
Options- A. increase
- B. decrease
- C. remain constant
- D. be excessive Discuss
- 5. A 140 Ω resistor is in parallel with an inductor having 60 Ω inductive reactance. Both components are across a 12 V ac source. The magnitude of the total impedance is
Options- A. 5.51 Ω
- B. 55.15 Ω
- C. 90 Ω
- D. 200 Ω Discuss
- 6. When converting 1,600 kilohms to megohms, the result is
Options- A. 1,600,000 MΩ
- B. 160 MΩ
- C. 1.6 MΩ
- D. 0.160 MΩ Discuss
- 7. The node voltage method is based on Kirchhoff's voltage law.
Options- A. True
- B. False Discuss
- 8. If the rms voltage drop across a 15 kΩ resistor is 16 V, the peak current through the resistor is
Options- A. 15 mA
- B. 1.5 mA
- C. 10 mA
- D. 1 mA Discuss
- 9. Referring to Problem 8, assume the input voltage is 15 V ac. What is the output voltage at the critical frequency,fc?
Options- A. 0 V
- B. 7.07 V
- C. 15 V
- D. 10.6 V Discuss
- 10. A certain series RLC circuit with a 200 Hz, 15 V ac source has the following values: R = 12 Ω, C = 80 µF, and L = 10 mH. The total impedance, expressed in polar form, is
Options- A. 12.28∠12.34° Ω
- B. 12.57∠12.34° Ω
- C. 9.95∠12.34° Ω
- D. 12.62∠12.34° Ω Discuss
More questions
Correct Answer: 2.2 kΩ
Correct Answer: 14.4 V
Explanation:
V = IR (Ohms Law)
= 12 X 10-3 X 1.2 X 10 3
= 12 X 1.2
= 14.4 V
Correct Answer: 3.84∠20.6° V
Correct Answer: decrease
Correct Answer: 55.15 Ω
Correct Answer: 1.6 MΩ
Correct Answer: False
Correct Answer: 1.5 mA
Correct Answer: 10.6 V
Correct Answer: 12.28∠12.34° Ω
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