AC machine frequency: To generate an 800 Hz sine wave with a four-pole (P = 4) generator, at what rotational speed in revolutions per second (rps) must the rotor run?

Difficulty: Easy

Correct Answer: 400 rps

Explanation:


Introduction / Context:
Synchronous generator frequency depends on the number of poles and mechanical speed. This relation is used to design alternators and set turbine speeds. Knowing how to back-calculate speed from a desired frequency is a practical skill.


Given Data / Assumptions:

  • Desired electrical frequency f = 800 Hz.
  • Number of poles P = 4.
  • We assume synchronous operation and rps (revolutions per second).


Concept / Approach:

The standard relation is f = (P/2) * n, where n is speed in rps. Solve for n = f / (P/2).


Step-by-Step Solution:

Compute pole pairs: P/2 = 4/2 = 2.Solve speed: n = f / (P/2) = 800 / 2 = 400 rps.Thus, the four-pole machine must run at 400 revolutions per second.


Verification / Alternative check:

In rpm, multiply by 60: 400 rps * 60 = 24,000 rpm, consistent with high-frequency generation requirements.


Why Other Options Are Wrong:

200 rps would give 400 Hz with four poles. 800 rps would produce 1,600 Hz. 1,600 rps would produce 3,200 Hz. None match 800 Hz.


Common Pitfalls:

Using rpm in the formula without converting; forgetting to divide poles by 2 (pole pairs).


Final Answer:

400 rps

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