Discussion
Home ‣ Electrical Engineering ‣ Branch, Loop and Node Analyses See What Others Are Saying!
- Question
In assigning the direction of branch currents,
Options- A. the directions are critical
- B. the directions are not critical
- C. they must point into a node
- D. they must point out of a node
- Correct Answer
- the directions are not critical
- 1. A complex number represents a phasor quantity.
Options- A. True
- B. False Discuss
- 2. To increase the current in a series RL circuit, the frequency
Options- A. should be increased
- B. should be decreased
- C. should be constant
- D. cannot be determined without values Discuss
- 3. You cannot convert a voltage source to an equivalent current source, or vice versa.
Options- A. True
- B. False Discuss
- 4. Power rating is related to resistance value.
Options- A. True
- B. False Discuss
- 5. In an RL high-pass filter, the output is taken across the inductor and the output leads the input.
Options- A. True
- B. False Discuss
- 6. A 15 V source is connected across a 12 Ω resistor. How much energy is used in three minutes?
Options- A. 938 Wh
- B. 0.938 Wh
- C. 56.25 Wh
- D. 5.6 Wh Discuss
- 7. A given power supply is capable of providing 6 A for 3.5 h. Its ampere-hour rating is
Options- A. 0.58 Ah
- B. 2.1 Ah
- C. 21 Ah
- D. 58 Ah Discuss
- 8. A loop current is an actual current in a branch.
Options- A. True
- B. False Discuss
- 9. A 12 V source has an internal resistance of 90 Ω. If a load resistance of 20 Ω is connected to the voltage source, the load power, PL, is
Options- A. 2.38 mW
- B. 2.38 W
- C. 238 mW
- D. 23.8 W Discuss
- 10. Five 100 Ω resistors are connected in parallel. If one resistor is removed, the total resistance is
Options- A. 25 Ω
- B. 500 Ω
- C. 100 Ω
- D. 20 Ω Discuss
More questions
Correct Answer: True
Correct Answer: should be decreased
Correct Answer: False
Correct Answer: False
Correct Answer: True
Correct Answer: 0.938 Wh
Correct Answer: 21 Ah
Correct Answer: False
Correct Answer: 238 mW
Correct Answer: 25 Ω
Explanation:
1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4 1/R = 1/100 + 1/100 + 100 + 1/100 1/R = 4/100 1/R = 1/25 Therefore R = 25 ohm.
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