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  • Question

  • A certain series circuit consists of a 1/8 W resistor, a 1/4 W resistor, and a 1/2 W resistor. The total resistance is 1200 Ω. If each resistor is operating in the circuit at its maximum power dissipation, total current flow is


  • Options
  • A. 27 mA
  • B. 2.7 mA
  • C. 19 mA
  • D. 190 mA

  • Correct Answer
  • 27 mA 

    Explanation
    Total P = P1 + P2 + P3 = 7/8w.

    P = I2R.

    I = sqrt (P/R)

    Now, P = 7/8w, R = 1200 ohm.

    Therefore,

    I= sqrt ( (7/8)/1200 ) = 0.0270030862 = 27 mA.

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    Comments

    Avatar
    Engineer MuF
    Can you guide and explain how to solve the above equation without using a calculator? Thank you in anticipation.
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