A certain series circuit consists of a 1/8 W resistor, a 1/4 W resistor, and a 1/2 W resistor. The total resistance is 1200 Ω. If each resistor is operating in the circuit at its maximum power dissipation, total current flow is
Options
A. 27 mA
B. 2.7 mA
C. 19 mA
D. 190 mA
Correct Answer
27 mA
Explanation
Total P = P1 + P2 + P3 = 7/8w.
P = I2R.
I = sqrt (P/R)
Now, P = 7/8w, R = 1200 ohm.
Therefore,
I= sqrt ( (7/8)/1200 ) = 0.0270030862 = 27 mA.
Series Circuits problems
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Can you guide and explain how to solve the above equation without using a calculator? Thank you in anticipation.