A certain series circuit consists of a 1/8 W resistor, a 1/4 W resistor, and a 1/2 W resistor. The total resistance is 1200 Ω. If each resistor is operating in the circuit at its maximum power dissipation, total current flow is
Options
A. 27 mA
B. 2.7 mA
C. 19 mA
D. 190 mA
Correct Answer
27 mA
Explanation
Total P = P1 + P2 + P3 = 7/8w.
P = I2R.
I = sqrt (P/R)
Now, P = 7/8w, R = 1200 ohm.
Therefore,
I= sqrt ( (7/8)/1200 ) = 0.0270030862 = 27 mA.
More questions
1. When the current through a 12 kΩ resistor is 8 mA, the power is
Because of 10% tolerance(last color silver), this resistance may vary 10% of 6800.
Minimum resistance value = 6800 - 680 = 6120
Maximum resistance value = 6800 + 680 = 7480
9. Four 8 Ω speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakers
Can you guide and explain how to solve the above equation without using a calculator? Thank you in anticipation.