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- Question
To measure the current out of the second resistor in a circuit consisting of four resistors, an ammeter can be placed
Options- A. between the second and third resistors
- B. at the negative terminal of the source
- C. between the third and fourth resistors
- D. at any point in the circuit
- Correct Answer
- at any point in the circuit
- 1. A string of five series resistors is connected across a 6 V battery. Zero voltage is measured across all resistors except R3. The voltage across R3 is
Options- A. 0 V
- B. 1.2 V
- C. 6 V
- D. 0.6 V Discuss
- 2. Two 1.5 V cells are connected series opposing across two 100 Ω resistors in series. Total current flow is
Options- A. 15 mA
- B. 5 mA
- C. 2 mA
- D. 0 A Discuss
- 3. The total resistance of a circuit is 680 Ω. The percentage of the total voltage appearing across a 47 Ω resistor that makes up part of the total series resistance is
Options- A. 68%
- B. 47%
- C. 69%
- D. 6.91% Discuss
- 4. Which of the following series combinations dissipates the most power when connected across a 120 V source?
Options- A. one 220 Ω resistor
- B. two 220 Ω resistors
- C. three 220 Ω resistors
- D. four 220 Ω resistors Discuss
- 5. The total resistance of eight 5.6 kΩ resistors in series is
Options- A. 8 Ω
- B. 5,600 Ω
- C. 4,480 Ω
- D. 44,800 Ω Discuss
- 6. If a 6 V and a 9 V source are connected series aiding, the total voltage is
Options- A. 6 V
- B. 9 V
- C. 3 V
- D. 15 V Discuss
- 7. A 12 V battery is connected across a series combination of 68 Ω, 47 Ω, 220 Ω, and 33 Ω. The amount of current is
Options- A. 326 mA
- B. 16.3 mA
- C. 32.6 mA
- D. 163 mA Discuss
- 8. A series circuit has a 24 V source and a total resistance of 120 Ω. The current through each resistor is
Options- A. 24 mA
- B. 200 mA
- C. 120 mA
- D. 20 mA Discuss
- 9. A certain series circuit consists of a 1/8 W resistor, a 1/4 W resistor, and a 1/2 W resistor. The total resistance is 1200 Ω. If each resistor is operating in the circuit at its maximum power dissipation, total current flow is
Options- A. 27 mA
- B. 2.7 mA
- C. 19 mA
- D. 190 mA Discuss
- 10. Three 680 Ω resistors are connected in series with a 470 V source. Current in the circuit is
Options- A. 69 mA
- B. 230 mA
- C. 23 mA
- D. 690 mA Discuss
Series Circuits problems
Search Results
Correct Answer: 6 V
Correct Answer: 0 A
Correct Answer: 6.91%
Correct Answer: one 220 Ω resistor
Correct Answer: 44,800 Ω
Correct Answer: 15 V
Correct Answer: 32.6 mA
Correct Answer: 200 mA
Correct Answer: 27 mA
Explanation:
Total P = P1 + P2 + P3 = 7/8w.
P = I2R.
I = sqrt (P/R)
Now, P = 7/8w, R = 1200 ohm.
Therefore,
I= sqrt ( (7/8)/1200 ) = 0.0270030862 = 27 mA.
P = I2R.
I = sqrt (P/R)
Now, P = 7/8w, R = 1200 ohm.
Therefore,
I= sqrt ( (7/8)/1200 ) = 0.0270030862 = 27 mA.
Correct Answer: 230 mA
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