Microampere current through a kilo-ohm resistor: for I = 200 µA flowing in R = 6.8 kΩ, compute the voltage drop across the resistor using V = I * R.

Introduction / Context:
Working with microampere currents and kilo-ohm resistors is common in sensor and instrumentation circuits. Converting prefixes correctly before applying V = I * R avoids common order-of-magnitude mistakes.

Given Data / Assumptions:

• I = 200 µA = 200 × 10^-6 A = 0.0002 A.
• R = 6.8 kΩ = 6.8 × 10^3 Ω = 6800 Ω.
• Compute V = I * R.

Concept / Approach:

Convert to base SI units, multiply, and then, if needed, present the result in convenient volts. A quick exponent check helps confirm the decimal placement.

Step-by-Step Solution:

Verification / Alternative check:

Power: P = V * I = 1.36 * 0.0002 = 0.000272 W = 0.272 mW, which is reasonable for small-signal applications.

Why Other Options Are Wrong:

13.6 V and 34.4 V are an order of magnitude too large; 340 V is two orders too large for these values.

Common Pitfalls:

Misreading µA as mA; forgetting to convert kΩ to Ω; slipping a decimal when multiplying.

Final Answer:

1.36 V