logo

CuriousTab

CuriousTab

Discussion


Home Electrical Engineering Ohm's Law Comments

  • Question
  • If you wish to increase the amount of current in a resistor from 120 mA to 160 mA by changing the 24 V source, what should the new voltage setting be?


  • Options
  • A. 8 V
  • B. 320 V
  • C. 3.2 V
  • D. 32 V

  • Correct Answer
  • 32 V 


  • Ohm's Law problems


    Search Results


    • 1. A resistance of 3.3 MΩ is connected across a 500 V source. The resulting current is approximately

    • Options
    • A. 15.1 µA
    • B. 151 µA
    • C. 66 mA
    • D. 660 mA
    • Discuss
    • 2. If 24 V are applied across a resistor and there are 10.9 mA of current, the resistance is

    • Options
    • A. 220 kΩ
    • B. 22 kΩ
    • C. 2.2 kΩ
    • D. 220 Ω
    • Discuss
    • 3. How much current is produced by a voltage of 18 kV across a 15 kΩ resistance?

    • Options
    • A. 1.2 A
    • B. 12 A
    • C. 120 mA
    • D. 12 mA
    • Discuss
    • 4. What is the approximate filament resistance of a light bulb if it operates from a 110 V source and 0.6 A of current is flowing?

    • Options
    • A. 183 Ω
    • B. 18.3 Ω
    • C. 66 Ω
    • D. 6.6 Ω
    • Discuss
    • 5. You are measuring the current in a circuit that is operated on an 18 V battery. The ammeter reads 40 mA. Later you notice the current has dropped to 20 mA. How much has the voltage changed?

    • Options
    • A. 9 V
    • B. 900 mV
    • C. 0 V
    • D. 18 V
    • Discuss
    • 6. An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately

    • Options
    • A. 385 Ω
    • B. 38.5 Ω
    • C. 3.1 Ω
    • D. 31 Ω
    • Discuss
    • 7. A current of 200 µA through a 6.8 kΩ resistor produces a voltage drop of

    • Options
    • A. 34.4 V
    • B. 340 V
    • C. 13.6 V
    • D. 1.36 V
    • Discuss
    • 8. A series circuit consists of three resistors with values of 120 Ω, 270 Ω, and 330 Ω. The total resistance is

    • Options
    • A. less than 120 Ω
    • B. the average of the values
    • C. 720 Ω
    • D. 120 Ω
    • Discuss
    • 9. Two resistors are in series: a 5.6 kΩ resistor and a 4.7 kΩ resistor. The voltage drop across the 5.6 kΩ resistor is 10 V. The voltage across the 4.7 kΩ resistor is

    • Options
    • A. 8.39 V
    • B. 10 V
    • C. 2.32 V
    • D. 0 V
    • Discuss
    • 10. Two 6 V batteries are connected series aiding across two 1.2 kΩ resistors in series. Current through each resistor is

    • Options
    • A. 5 mA
    • B. 10 mA
    • C. 0 A
    • D. 2.5 mA
    • Discuss


    Comments

    There are no comments.

Enter a new Comment