For reducing or attenuating high-frequency components in an electrical circuit, which type of component should be used?

Difficulty: Easy

Correct Answer: Inductance

Explanation:


Introduction / Context:
In electronic circuits, filtering and attenuation of high frequencies is often required to suppress noise or to achieve desired frequency response. Different components respond differently to frequency, making some more suitable for attenuating high-frequency signals.



Given Data / Assumptions:

  • We want to attenuate high frequencies.
  • We can choose among capacitors, inductors, and resistors.


Concept / Approach:

Inductors present reactance XL = 2πfL, which increases with frequency. Thus, as frequency increases, an inductor increasingly resists current flow, attenuating high-frequency signals. Conversely, capacitive reactance decreases with frequency, making capacitors pass high frequencies rather than attenuate them.



Step-by-Step Solution:

XL = 2πfL.As frequency f increases, XL increases linearly.Therefore, inductors block or attenuate high-frequency signals effectively.


Verification / Alternative check:

Low-pass filters are often constructed with series inductors and shunt capacitors to block high frequencies and pass low frequencies.



Why Other Options Are Wrong:

  • Shunt capacitance: passes high frequencies, not attenuates them.
  • Series capacitance: blocks low frequencies, passes high, opposite effect.
  • Resistance: attenuates all frequencies equally, not selective.
  • Parallel resonance: attenuates only at a narrow band, not all high frequencies.


Common Pitfalls:

Assuming resistance is sufficient for selective attenuation; forgetting inductors inherently resist higher frequencies.



Final Answer:

Inductance

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