AB + AB = B A 1 0 AB + AB = A(B + B) = A . 1 = A.

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Correct Answer

A

Explanation

AB + AB = A(B + B) = A . 1 = A.

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2. In a BCD to 7 segment decoder the minimum and maximum number of outputs active at any time is
Options
A. 2 and 7
B. 3 and 7
C. 1 and 6
D. 3 and 6

5. BCD input 1000 is fed to a 7 segment display through a BCD to 7 segment decoder/driver. The segments which will lit up are
Options
A. a, b, d
B. a, b, c
C. all
D. a, b, g, c, d

6. A three state switch has three outputs. These are
Options
A. low, low and high
B. low, high, high
C. low. floating, low
D. low, high, floating

7. The circuit of the given figure realizes the function
Options
A. Y = (A + B) C + DE
B. Y = A + B + C + D + E
C. AB + C +DE
D. AB + C(D + E)

8. In register index addressing mode the effective address is given by
Options
A. index register value
B. sum of the index register value and the operand
C. operand
D. difference of the index register value and the operand

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