An impulse function consist of pure dc pure a.c entire frequency range with cons

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Question
An impulse function consist of
Options
A. pure dc
B. pure a.c
C. entire frequency range with constant phase
D. infinite bandwidth with linear phase vaariations

Correct Answer

entire frequency range with constant phase

Explanation

Because F.T. of ?(t) = 1, 1 is a Constant function ranging from -? to +?.

Signals and Systems problems

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1. Consider Pole zero diagram as shown, If two Poles are moved in opposite direction towards ? = p/2 and -p/2, the filter will be
Options
A. change to high pass filter
B. change to Band Pass filter
C. remains same
D. change to LPF

3. In an ac circuit the fundamental component of current wave lags the corresponding voltage wave by 20�. The third harmonic component of current wave lags the corresponding voltage by an angle.
Options
A. less than 20�
B. more than 20�
C. equal to 20�
D. equal to or more than 20�

5. Assertion (A): If , the initial value of i(t) is 5A
Reason (R): As per initial vaue theroem
Options
A. Both A and R are correct and R is correct explanation of A
B. Both A and R are correct but R is not correct explanation of A
C. A is true, R is false
D. A is false, R is true

6. The continuous time system with impulse response h(t) = is stable, for n is even, when
Options
A. a = 0
B. a > 0
C. a < 0
D. a ? 0

7. For a given voltage, four heating coils will produce maximum heat when connected
Options
A. all in parallel
B. all in series
C. with two parallel pairs in series
D. one pair in parallel with the other two in series

8. A radar receiver has a noise figure of 10 dB at 300 K having a bandwidth of 2.5 MHz. The minimum power it can receive is
Options
A. 3.45 x 10^-15 W
B. 1.38 x 10^-15 W
C. 7.5 x 10^-15 W
D. 93.15 x 10^-15 W

9. Consider the probability density f(x) = ae^-b|x| where x is a random variable whose allowable values range from x = - ? to x = + ?. P(1 ? x ? 2)
Options
A.
B.
C.
D. (e^-b - e^-2b)

10. Find 'X' in the circuit below :

f₁(A, B, C, D) = ?(6, 7, 13, 14);
f₂(A, B, C, D) = ?(3, 6, 7);
f₃(A, B, C, D) = ?(5, 6, 7, 14, 15)
Options
A. p(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 15)
B. 0
C. ?(14)
D. 1

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