The simplest triangles are APQ, AEQ, QTU, QRU, BGS, BHS, RSU, SUV, TUW, UWX, NWD, WDM, UVY, UXY, JCY and YKC i.e. 16 in number.
The triangles composed of two components each are QUW, QSU, SYU and UWY i.e. 4 in number.
The triangles composed of three components each are AOU, AFU, FBU, BIU, UIC, ULC, ULD and OUD i.e. 8 in number.
The triangles composed of four components each are QYW, QSW, QSY and SYW i.e. 4 in number.
The triangles composed of six components each are AUD, ABU, BUC and DUC i.e. 4 in number.
The triangles composed of seven components each are QMC, ANY, EBW, PSD, CQH, AGY, DSK and BJW i.e. 8 in number.
The triangles composed of twelve components each are ABD, ABC, BCD and ACD i.e. 4 in number.
Thus, there are 16 + 4 + 8 + 4 + 4 + 8 + 4 = 48 triangles in the figure.
After opening the first fold it will look like as:
When it is unfolded completely it will look like as:
In this question, the sets of numbers given in the alternatives are represented. The columns and rows of Matrix I are numbered from 0 to 4 and that of Matrix II are numbered from 5 to 9. A letter from these matrices can be represented first by its row and next by its column, e.g., 'K' can be represented by 41,34, etc., and 'Z' can be represented by 75, 86, etc. Similarly you have to identify the set for the word 'PAWN'.
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From Problem Figure (1) to (2) the design is inverted horizontally. In other words, the second figure is the mirror image of the first figure.
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