Select a suitable figure from the Answer Figures that would replace the question mark (?).

Problem Figures:                            Answer Figures:

    (A)     (B)      (C)     (D)                  (1)      (2)      (3)      (4)      (5)

The half-arrow rotates 90 ^oACW and gets laterally inverted and moves to the adjacent side of the square boundary in a CW direction. The bent pin rotates 90 ^oACW and moves to the adjacent side of the square boundary in a CW direction.

In the upper and the lower elements, the white part turns black and the black turns white. In the central arrow, one of the arrowheads from the LHS gets laterally inverted and moves to the RHS.

The LHS element becomes a closed figure by combining with three similar elements. The RHS element gets reduced in size, turns black and moves to the centre of the other figure.

The lower element gets enlarged and becomes the outermost element; the upper element gets slightly enlarged and becomes the middle element and a new element with one more number of sides than the lower element appears as the innermost element.

The figure rotates through 180 ^o.

The two elements interchange positions; the element that reaches the LHS position gets vertically inverted and the element that reaches the RHS position, rotates 90 ^oACW.

The figure rotates 90 ^oCW and gets laterally inverted.

The existing line segments that join the corners of the squares move to the adjacent corners in an ACW direction and one more line segment appears in the next corner at the ACW-end. The shading inside the innermost square changes from dots to slanting lines.

All the arrows reverse their directions.

The figure may be labelled as shown.

The simplest triangles are ABG, BCG, CGE, CDE, AGE and AEF i.e. 6 in number.

The triangles composed of two components each are ABE, ABC, BCE and ACE i.e. 4 in number.

There are 6 + 4 = 10 triangles in the figure.