A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:

Let the son's present age be x years. Then, man's present age = (x + 24) years.

∴ (x + 24) + 2 = 2(x + 2)

⟹ x + 26 = 2x + 4

⟹ x = 22.

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

⟹ 3x + 20 = 2x + 40

⟹ x = 20.

∴ Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

Then,	5x + 3	=	11
	4x + 3		9

⟹ 9(5x + 3) = 11(4x + 3)

⟹ 45x + 27 = 44x + 33

⟹ 45x - 44x = 33 - 27

⟹ x = 6.

∴ Anand's present age = 4x = 24 years.

Given that:

1. The difference of age b/w R and Q = The difference of age b/w Q and T.

2. Sum of age of R and T is 50 i.e. (R + T) = 50.

Question: R - Q = ?.

Explanation:

R - Q = Q - T

(R + T) = 2Q

Now given that, (R + T) = 50

So, 50 = 2Q and therefore Q = 25.

Question is (R - Q) = ?

Here we know the value(age) of Q (25), but we don't know the age of R.

Therefore, (R-Q) cannot be determined.

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Then,	(6x + 6) + 4	=	11
	(5x + 6) + 4		10

⟹ 10(6x + 10) = 11(5x + 10)

⟹ 5x = 10

⟹ x = 2.

∴ Sagar's present age = (5x + 6) = 16 years.

Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,

4x + 6 = 26    ⟺    4x = 20

x = 5.

∴ Deepak's age = 3x = 15 years.

Let Rahul's age be x years.

Then, Sachin's age = (x - 7) years.

∴	x - 7	=	7
	x		9

⟹ 9x - 63 = 7x

⟹ 2x = 63

⟹ x = 31.5

Hence, Sachin's age =(x - 7) = 24.5 years.

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

⟹ 5x = 20

⟹ x = 4.

∴ Age of the youngest child = x = 4 years.

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

⟹ 20x = 80

⟹ x = 4.

∴ Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

∴ (2x + 2) + 2x + x = 27

⟹ 5x = 25

⟹ x = 5.

Hence, B's age = 2x = 10 years.