Whole work is done by A in | ❨ | 20 x | 5 | ❩ | = 25 days. |
4 |
Now, | ❨ | 1 - | 4 | ❩ | i.e., | 1 | work is done by A and B in 3 days. |
5 | 5 |
Whole work will be done by A and B in (3 x 5) = 15 days.
A's 1 day's work = | 1 | , (A + B)'s 1 day's work = | 1 | . |
25 | 15 |
∴ B's 1 day's work = | ❨ | 1 | - | 1 | ❩ | = | 4 | = | 2 | . |
15 | 25 | 150 | 75 |
So, B alone would do the work in | 75 | = 37 | 1 | days. |
2 | 2 |
A's 1 hour's work = | 1 | ; |
4 |
(B + C)'s 1 hour's work = | 1 | ; |
3 |
(A + C)'s 1 hour's work = | 1 | . |
2 |
(A + B + C)'s 1 hour's work = | ❨ | 1 | + | 1 | ❩ | = | 7 | . |
4 | 3 | 12 |
B's 1 hour's work = | ❨ | 7 | - | 1 | ❩ | = | 1 | . |
12 | 2 | 12 |
∴ B alone will take 12 hours to do the work.
10 | 1 | days |
2 |
(B + C)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 7 | . |
9 | 12 | 36 |
Work done by B and C in 3 days = | ❨ | 7 | x 3 | ❩ | = | 7 | . |
36 | 12 |
Remaining work = | ❨ | 1 - | 7 | ❩ | = | 5 | . |
12 | 12 |
Now, | 1 | work is done by A in 1 day. |
24 |
So, | 5 | work is done by A in | ❨ | 24 x | 5 | ❩ | = 10 days. |
12 | 12 |
1 | day |
24 |
7 | day |
24 |
3 | 3 | days |
7 |
3 | 3 | days |
7 |
Formula: If A can do a piece of work in n days, then A's 1 day's work = | 1 | . |
n |
(A + B + C)'s 1 day's work = | ❨ | 1 | + | 1 | + | 1 | ❩ | = | 7 | . |
24 | 6 | 12 | 24 |
Formula: If A's 1 day's work = | 1 | , | then A can finish the work in n days. |
n |
So, all the three together will complete the job in | ❨ | 24 | ❩ days | = | 3 | 3 | days. |
7 | 7 |
Then, x + y = | 1 | and 16x + 44y = 1. |
30 |
Solving these two equations, we get: x = | 1 | and y = | 1 |
60 | 60 |
∴ B's 1 day's work = | 1 | . |
60 |
Hence, B alone shall finish the whole work in 60 days.
5 | 1 |
2 |
B's 10 day's work = | ❨ | 1 | x 10 | ❩ | = | 2 | . |
15 | 3 |
Remaining work = | ❨ | 1 - | 2 | ❩ | = | 1 | . |
3 | 3 |
Now, | 1 | work is done by A in 1 day. |
18 |
∴ | 1 | work is done by A in | ❨ | 18 x | 1 | ❩ | = 6 days. |
3 | 3 |
20 | 3 | days |
17 |
Suppose B takes x days to do the work.
Then, 10 : 13 :: 23 : x ⟹ x = | ❨ | 23 x 13 | ❩ | ⟹ x = | 299 | . |
10 | 10 |
A's 1 day's work = | 1 | ; |
23 |
B's 1 day's work = | 10 | . |
299 |
(A + B)'s 1 day's work = | ❨ | 1 | + | 10 | ❩ | = | 23 | = | 1 | . |
23 | 299 | 299 | 13 |
Therefore, A and B together can complete the work in 13 days.
(A + B)'s 20 day's work = | ❨ | 1 | x 20 | ❩ | = | 2 | . |
30 | 3 |
Remaining work = | ❨ | 1 - | 2 | ❩ | = | 1 | . |
3 | 3 |
Now, | 1 | work is done by A in 20 days. |
3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
S.I. = Rs | ❨ | 1200 x 10 x 1 | ❩ | = Rs. 120. |
100 |
C.I. = Rs. | [ | 1200 x | ❨ | 1 + | 5 | ❩ | 2 | - 1200 | ] | = Rs. 123. |
100 |
∴ Difference = Rs. (123 - 120) = Rs. 3.
Sum = Rs. | ❨ | 50 x 100 | ❩ | = Rs. 500. |
2 x 5 |
Amount |
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= Rs. 551.25 |
∴ C.I. = Rs. (551.25 - 500) = Rs. 51.25
Amount |
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= Rs. 8820. |
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