3x + y = 243 = 35 ⟺ x + y = 5 ....(ii)
On solving (i) and (ii), we get x = 4.
Then, B's share = Rs. | x | , A's share = Rs. | ❨ | 2 | x | x | ❩ | = Rs. | x |
4 | 3 | 4 | 6 |
∴ | x | + | x | + x = 1360 |
6 | 4 |
⟹ | 17x | = 1360 |
12 |
⟹ x = | 1360 x 12 | = Rs. 960 |
17 |
Hence, B's share = Rs. | ❨ | 960 | ❩ | = Rs. 240. |
4 |
Then, 2x + 4y = 1600 .... (i)
and x + 6y = 1600 .... (ii)
Divide equation (i) by 2, we get the below equation. => x + 2y = 800. --- (iii) Now subtract (iii) from (ii) x + 6y = 1600 (-) x + 2y = 800 ---------------- 4y = 800 ---------------- Therefore, y = 200. Now apply value of y in (iii) => x + 2 x 200 = 800 => x + 400 = 800 Therefore x = 400
Solving (i) and (ii) we get x = 400, y = 200.
∴ Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.
Then, the capacity of tank = 25x.
New capacity of bucket = | 2 | x |
5 |
∴ Required number of buckets = | 25x |
(2x/5) |
= | ❨ 25x | x | 5 | ❩ |
2x |
= | 125 |
2 |
= 62.5
Then, x + y = 48 .... (i)
and 2x + 4y = 140 ⟹ x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
∴ The required answer = 26.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
∴ 160 x 2.40 + x x 3.20 = 432
⟹ 3.20x = 432 - 384 = 48
⟹ x = 15.
Hence, total hours of work = (160 + 15) = 175.
Then, | (52)7.5 x (5)2.5 | = 5x |
(53)1.5 |
⟹ | 5(2 x 7.5) x 52.5 | = 5x |
5(3 x 1.5) |
⟹ | 515 x 52.5 | = 5x |
54.5 |
⟹ 5x = 5(15 + 2.5 - 4.5)
⟹ 5x = 513
∴ x = 13.
❨ | xb | ❩ | (b + c - a) | . | ❨ | xc | ❩ | (c + a - b) | . | ❨ | xa | ❩ | (a + b - c) | =? |
xc | xa | xb |
Given Exp. |
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Putting m = 11 and n = 2, we get:
(m - 1)n + 1 = (11 - 1)(2 + 1) = 103 = 1000.
⟹ 0.48z = 1.40
⟹ z = | 140 | = | 35 | = 2.9 (approx.) |
48 | 12 |
If | ❨ | a | ❩ | x - 1 | = | ❨ | b | ❩ | x - 3 | , then the value of x is: |
b | a |
Given ❨ | a | ❩ | x - 1 | = | ❨ | b | ❩ | x - 3 |
b | a |
⟹ | ❨ | a | ❩ | x - 1 | = | ❨ | a | ❩ | -(x - 3) | = | ❨ | a | ❩ | (3 - x) |
b | b | b |
⟹ x - 1 = 3 - x
⟹ 2x = 4
⟹ x = 2.
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