Then, 2x + 4y = 1600 .... (i)
and x + 6y = 1600 .... (ii)
Divide equation (i) by 2, we get the below equation. => x + 2y = 800. --- (iii) Now subtract (iii) from (ii) x + 6y = 1600 (-) x + 2y = 800 ---------------- 4y = 800 ---------------- Therefore, y = 200. Now apply value of y in (iii) => x + 2 x 200 = 800 => x + 400 = 800 Therefore x = 400
Solving (i) and (ii) we get x = 400, y = 200.
∴ Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.
22 | 1 | days |
2 |
22 | 1 | days |
2 |
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes | ❨ | 3 | x 60 | ❩ | = 90 days. |
2 |
So, A takes 30 days to do the work.
A's 1 day's work = | 1 |
30 |
B's 1 day's work = | 1 |
90 |
(A + B)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 4 | = | 2 |
30 | 90 | 90 | 45 |
∴ A and B together can do the work in | 45 | = 22 | 1 | days. |
2 | 2 |
Distance between Raipur and Somgarh
= Average speed x Time
= 69 x 35/60= 161/4 km
New speed = (69 + 36) km/h = 105 km/h
? Time = Distance/ Speed = 161/4 x 105 h
= 161 x 60/4 x 105min = 23 min
Let the number of soldiers transferred be N
Now, the food would last for 25 days for (2000 - N) soldiers.
Less men, More days (indirect proportion)
25 : 20 : : 2000 : (2000 - N)
? 2000 - N = (2000 x 20)/25
? 2000 - N = 1600
? N = 2000 - 1600 = 400
The required greatest number is the HCF of (263 - 7, 935 - 7, 1383 - 7)
i.e., HCF of 256, 928 and 1376 = 32
Let the number be 16a and 16b, where a and be are two number prime to each other.
? 16a x 16b = 7168
? ab = 28
Now, the pairs of number whose products is 28, are (28, 1) : (14, 2), (7,4)
14 and 2 which are not prime to each other should be rejected.
Hence, the required answer
= (448 + 16) + (112 + 64) = 640
In a 800 meter race, A covers 800 meter while B cover 760 meter.
? A covers 200 m while B will cover 760 x 200 / 800 = 190 m
Again, B covers 500 m while C 495 m
? B covers 190 m while C will cover = 495 x 190 / 500 = 188.10 m
Since, A covers 200 m while C 188.10 m
Hence, A will beat C by (200 ? 188.10) = 11.9 m
Given. ratio = 7/2 : 4/3 : 6/5
= (7/2) x 30 : (4/3) x 30 : (6/5) x 30
= 105 : 40 : 36
Let investment of Amitabh = 105k
Investment of Kamlesh = 36k
Ratio of their investments
= [105k x 4 + 150% x8 of 105k] : (40k x 12) : (36k x 12)
= (420k + (150/100) x 105k x 8) : (480k) : (432k)
= (1680k) : (480k) : (432k)
= 35 : 10 : 9
? Brijesh's share
= (21600 x 10) / (35 + 10 + 9)
= (21600 x 10) / 54
= ? 4000
As per given question,
In 1 minute, 6 identical machines can produce a total of 270 bottles.
In 1 minute, 1 identical machines can produce a total of 270 / 6 bottles.
In 1 minute, 10 identical machines can produce a total of 270 x 10 / 6 bottles.
In 4 minute, 10 identical machines can produce a total of 270 x 10 x 4 / 6 bottles.
In 4 minute, 10 identical machines can produce a total of 45 x 10 x 4 bottles.
In 4 minute, 10 identical machines can produce a total of 1800 bottles.
Let money lent at 12% Rs. P
Then, money lent at 121/2% = Rs. (2540 - P )
? (P x 12 x 1)/100 + {(2540 - P) x 25/2 x 1}/100 = 311.60
? 3P/25 + 2540 - P/8 = 311.60
? 24P + 25(2540 - P) = 200 x 311.60
? P = 63500 - 62320 = 1180
160 = ?1600 x B.G.
? B.G. = (160 x 160)/1600 = Rs. 16
? Banker's discount = 160 + 16 = Rs. 176
[? B.D. = T.D. + B.G.]
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.