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- Question
The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay?
Options- A. Rs. 1200
- B. Rs. 2400
- C. Rs. 4800
- D. Cannot be determined
- E. None of these
- Correct Answer
- Rs. 2400
Explanation
Let the price of a saree and a shirt be Rs. x and Rs. y respectively.Then, 2x + 4y = 1600 .... (i)
and x + 6y = 1600 .... (ii)
Divide equation (i) by 2, we get the below equation. => x + 2y = 800. --- (iii) Now subtract (iii) from (ii) x + 6y = 1600 (-) x + 2y = 800 ---------------- 4y = 800 ---------------- Therefore, y = 200. Now apply value of y in (iii) => x + 2 x 200 = 800 => x + 400 = 800 Therefore x = 400Solving (i) and (ii) we get x = 400, y = 200.
∴ Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.
- 1. A and B together can complete a work in 3 days. They started together but after 2 days, B left the work. If the work is completed after 2 more days, B alone could do the work in how many days?
Options- A. 5
- B. 6
- C. 7
- D. 10 Discuss
- 2. A wheel makes 1000 revolutions in covering a distance of 88 km. the diameter of the wheel is?
Options- A. 24 meters
- B. 40 meters
- C. 28 meters
- D. 14 meters Discuss
- 3. 25, 36, 49, 81, 121, 169, 225
Options- A. 36
- B. 49
- C. 121
- D. 169 Discuss
- 4. (.896 x .752 +.896 x .248) / (.7 x .034 + .7 x.966) =?
Options- A. 1.28
- B. 0.976
- C. 12.8
- D. 9.76 Discuss
- 5. Einstein goes from Ahmedabad To Lucknow at the speed of 40 km/hr and returned at the speed of 60 km/hr .the average speed of Einstein during the whole journey is
Options- A. 48 km/hr
- B. 24 km/hr
- C. 50 km/hr
- D. none of these Discuss
- 6. Today is Monday. After 61 days, it will be
Options- A. Wednesday
- B. Saturday
- C. Tuesday
- D. Thursday Discuss
- 7. 9548 + 7314 = 8362 + (?)
Options- A. 8230
- B. 8410
- C. 8500
- D. 8600
- E. None of these Discuss
- 8. The true discount on a certain sum due 1 yr hence at 30% per annum, is ? 240. What is the banker' discount on the same sum for the same time and at the same rate?
Options- A. ? 400
- B. ? 212
- C. ? 312
- D. ? 445 Discuss
- 9. Calendar of month July is same as that of which month of previous year.
Options- A. May
- B. September
- C. April
- D. None of these Discuss
- 10. A coin is successively tossed two times. Find the probability of getting? (1) exactly one head (2)at least one head
Options- A. 1/2 , 3/4
- B. 2/3, 1/4
- C. 1/4, 4/5
- D. 1/2, 2/3 Discuss
More questions
Correct Answer: 6
Explanation:
(A + B)'s 2 day's work = 2 x (1/3) = 2/3
Remaining work = 1 - (2/3) = 1/3
A will complete 1/3 work in 2
A will complete 1 work in 6
A's 1 days work = 1/6
B's 1 day's work = (1/3) - (1/6) = 1/6
? B will take 6 days to complete the work alone.
Correct Answer: 28 meters
Explanation:
Distance covered in one revolution = total distance travelled / total number of revolution.
= ( 88 x 1000) / 1000 m
= 88 m
We know that the distance covered in one revolution = circumference of the wheel.
? ?d = 88
? 22d / 7 = 88
? d = 28 m
Correct Answer: 36
Explanation:
So, 36 is wrong.
Correct Answer: 1.28
Explanation:
Given expression = (.896 x .752 +.896 x .248) / (.7 x .034 + .7 x.966)
=.[896 x (.752+.248)] / [.7 x (.034+.966)]
= .(896 x 1) / ( .700 x 1)
=896/700
= 1.28
Correct Answer: 48 km/hr
Explanation:
Average speed =2 x 40 x 60 / ( 40+ 60)
= 4800 / 100
= 48 km/hr
Correct Answer: Saturday
Explanation:
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
Correct Answer: 8500
Explanation:
9548 16862 = 8362 + x + 7314 x = 16862 - 8362 ----- = 8500 16862 -----
Correct Answer: ? 312
Explanation:
We know that
BG = SI on TD = (240 x 30 x 1 x 1)/100
= ? 72
BG = BD - TD
? BD = BG + TD
= 72 + 240
= ? 312
Correct Answer: May
Explanation:
If previous year is leap year then calendar of May is similar to July
Correct Answer: 1/2 , 3/4
Explanation:
In tossing a coin 2 times the sample space is 4 i,e (H, H), (H, T), (T, H), (T, T)
(1) If A1 denotes exactly one head
then A1 = {(H, T) (T, H) }
So, P(A1 ) = 2/4 = 1/2
(2) If A denotes at least one head
then A = {(H, T) (T, H) (H, H)}
? A = {(H, T) (T, H) (H, H )}
? P(A) = 3/4
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