Then, 13a x 13b = 2028
⟹ ab = 12.
Now, the co-primes with product 12 are (1, 12) and (3, 4).
[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).
Clearly, there are 2 such pairs.
17 | 6 | km/hr |
7 |
Time taken = 1 hr 40 min 48 sec = 1 hr 40 | 4 | min = 1 | 51 | hrs = | 126 | hrs. |
5 | 75 | 75 |
Let the actual speed be x km/hr.
Then, | 5 | x x | 126 | = 42 |
7 | 75 |
⟹ x = | ❨ | 42 x 7 x 75 | ❩ | = 35 km/hr. |
5 x 126 |
63 |
487 |
119 |
993 |
125 |
999 |
125 |
999 |
0.125125... = 0.125 = | 125 |
999 |
5 | 1 |
4 |
13 | 1 |
2 |
Other side | = |
|
ft | ||||||||||||
= |
|
ft | |||||||||||||
= |
|
ft | |||||||||||||
= | 6 ft. |
∴ Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.
Let l = 4k and b = 9k
Area of rectangle = l x b
144 = 4k x 9k
? k2 = 144/36
? k2 = 4
? k = 2
? l = 8 cm and b = 18 cm
Perimeter of rectangle = 2(l + b)
= 2(8 + 18)
= 2 x 26
= 52 cm
If the trains meet after t h.
Relative speed of train = (24 -18) = 6 km/h
? Distance = 27
? t = 27/6 = 9/2 h
? QR distance travel by train which is travelling at a speed of 18 km/h = 18t = 18 x 9/2 = 81 km
Let the number be a and b
Then, (a-b) = (a2 - b2) / a+b
= 145/29
= 5
Let the four consecutive even number are x, ( x+2), (x+4), (x+6).
Clearly this is a series of consecutive even numbers
According to the formula,
Average of consecutive numbers = (first number + last number)/ 2
? 27 = [x + (x + 6)]/2
? x + 3 = 27
? x =24
? Greatest number = 4th consecutive even number = (x + 6) = 24 + 6 = 30
Let the name of the man be A and that of his wife be B. Then ,P(A will not be alive after 10 yr and B will not be alive after 10yr) = 3/4 x 2/3 = 1/2
Total number of ways of selecting one number from 25 number is 25C1 ways.
Let E be the event of drawing a number divisible by both 2 and 3
i.e., (if a number is divisible by both 2 and 3, it is divisible by 6 also)
E = {6, 12, 18, 24}
? Required probability = P(E) = n(E) / n(S) = 4/25
Average = (0.64204 + 0.64203 + 0.64202 + 0.64201)/ 4
=2.5681/ 4
=0.642025
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