logo

CuriousTab

CuriousTab

Discussion


Home Aptitude Problems on H.C.F and L.C.M Comments

  • Question
  • The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:


  • Options
  • A. 1
  • B. 2
  • C. 3
  • D. 4

  • Correct Answer


  • Explanation
    Let the numbers 13 a and 13 b

    Then, 13a x 13b = 2028

    ab = 12.

    Now, the co-primes with product 12 are (1, 12) and (3, 4).

    [Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]

    So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).

    Clearly, there are 2 such pairs.

  • Tags: AIEEE, Bank Exams, CAT, GRE, TOEFL, Bank Clerk, Bank PO, Analyst

    Problems on H.C.F and L.C.M


    Search Results


    • 1. The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

    • Options
    • A. 74
    • B. 94
    • C. 184
    • D. 364
    • Discuss
    • 2. What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?

    • Options
    • A. 196
    • B. 630
    • C. 1260
    • D. 2520
    • Discuss
    • 3. Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:

    • Options
    • A. 40
    • B. 80
    • C. 120
    • D. 200
    • Discuss
    • 4. The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

    • Options
    • A. 1677
    • B. 1683
    • C. 2523
    • D. 3363
    • Discuss
    • 5. Reduce 128352/238368 to its lowest terms

    • Options
    • A. 34
    • B. 513
    • C. 713
    • D. 913
    • Discuss
    • 6. Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together?

    • Options
    • A. 4
    • B. 10
    • C. 15
    • D. 16
    • Discuss
    • 7. Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

    • Options
    • A. 4
    • B. 5
    • C. 6
    • D. 8
    • Discuss
    • 8. If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

    • Options
    • A. 55601
    • B. 60155
    • C. 11120
    • D. 12011
    • Discuss
    • 9. The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

    • Options
    • A. 101
    • B. 107
    • C. 111
    • D. 185
    • Discuss
    • 10. Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:

    • Options
    • A. 75
    • B. 81
    • C. 85
    • D. 89
    • Discuss


    Comments

    There are no comments.

Enter a new Comment