∴(6767 + 1) will be divisible by (67 + 1)
∴(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
(217)2 + (183)2 | = (200 + 17)2 + (200 - 17)2 |
= 2 x [(200)2 + (17)2] [Ref: (a + b)2 + (a - b)2 = 2(a2 + b2)] | |
= 2[40000 + 289] | |
= 2 x 40289 | |
= 80578. |
This is a G.P. in which a = 2, r = | 22 | = 2 and n = 9. |
2 |
∴Sn = | a(rn - 1) | = | 2 x (29 - 1) | = 2 x (512 - 1) = 2 x 511 = 1022. |
(r - 1) | (2 - 1) |
1904 x 1904 | = (1904)2 |
= (1900 + 4)2 | |
= (1900)2 + (4)2 + (2 x 1900 x 4) | |
= 3610000 + 16 + 15200. | |
= 3625216. |
The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.
Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 9.
∴Required value of * is 6.
Given Exp. | = (397)2 + (104)2 + 2 x 397 x 104 |
= (397 + 104)2 | |
= (501)2 = (500 + 1)2 | |
= (5002) + (1)2 + (2 x 500 x 1) | |
= 250000 + 1 + 1000 | |
= 251001 |
9 + | 3 | + 7 + | 2 | - | ❨ | 9 + | 1 | ❩ | =? |
4 | 17 | 15 |
Given sum |
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(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.
3897 x 999 | = 3897 x (1000 - 1) |
= 3897 x 1000 - 3897 x 1 | |
= 3897000 - 3897 | |
= 3893103. |
Given Exp. = | 800 | x | 1296 | = 450 |
64 | 36 |
2056 x 987 | = 2056 x (1000 - 13) |
= 2056 x 1000 - 2056 x 13 | |
= 2056000 - 26728 | |
= 2029272. |
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