C.P. of 1st transistor = Rs. | ❨ | 100 | x 840 | ❩ | = Rs. 700. |
120 |
C.P. of 2nd transistor = Rs. | ❨ | 100 | x 960 | ❩ | = Rs. 1000 |
96 |
So, total C.P. = Rs. (700 + 1000) = Rs. 1700.
Total S.P. = Rs. (840 + 960) = Rs. 1800.
∴ Gain % = | ❨ | 100 | x 100 | ❩% | = 5 | 15 | % |
1700 | 17 |
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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