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- Question
How should a router that is being used in a Frame Relay network be configured to keep split horizon issues from preventing routing updates
Options- A. Configure a seperate subinterface for each PVC with a unique DLCI and subnet assigned to the subinterface
- B. Combine multiple Frame Relay circuits as a point-to-point line to support multicast and broadcast traffic
- C. Configure many subinterfaces in the same subnet
- D. Configure a single subinterface to establish multiple PVC connections to multiple remote router interfaces.
- Correct Answer
- Configure a seperate subinterface for each PVC with a unique DLCI and subnet assigned to the subinterface
ExplanationIf you have a serial port configured with multiple DLCIs connected to multiple remote sites, split horizon rules stop route updates received on an interface from being sent out the same interface. By creating subinterfaces for each PVC, you can avoid the split horizon issues when using Frame Relay.
- 1. You need to configure a router for a Frame Relay connection to a non-Cisco router. Which of the following commands will prepare the WAN interface of the router for this connection?
Options- A. Router (config-if) #encapsulation frame-relay q933a
- B. Router (config - if) #encapsulation frame-relay ansi
- C. Router (config - if) #encapsulation frame-relay ietf
- D. Router (config - if) #encapsulation frame-relay cisco Discuss
- 2. Which type of address is used just like a regular public routable address in IPv4? Discuss
- 3. You want to ping the loopback address of your IPv6 local host. What will you type?
Options- A. Ping 127.0.0.1
- B. Ping 0.0.0.0
- C. Ping ::1
- D. trace 0.0. :: 1 Discuss
- 4. What device must be on your wired network when running an enterprise EAP solution? Discuss
- 5. Which IEEE committee has been sanctioned by WAP and is called WPA2? Discuss
- 6. What protocol would you use if you were running xDSL and needed authentication? Discuss
- 7. Assume a router has a loopback address of 135.77.9.254. Convert the loopback address to an IS-IS system ID. Discuss
- 8. What is the purpose of the LOCAL_PREF attribute? Discuss
- 9. You are the network administrator and are given the tasks to plan for the future expansion of the network. You decide to subnet the current network of 172.15.0.0. What will be the subnet mask be if every subnet has to allocate 500 hosts.
Options- A. 255.255.0.0
- B. 255.0.0.0
- C. 255.255.240.0
- D. 255.255.254.0 Discuss
- 10. Given the following network range 192.168.0.0/24. We want minimum 50 hosts on each of the available subnets. What will be the subnet mask?
Options- A. /24
- B. /25
- C. /26
- D. /27 Discuss
CISCO Certification problems
Search Results
Correct Answer: Router (config - if) #encapsulation frame-relay ietf
Explanation:
If you have a Cisco router on one side of a Frame Relay network and a non-Cisco router on the otherside, you would need to use the Frame Relay encapsulation type of IETF. The default is Cisco encapsulation, which means that a Cisco router must be on both sides of the Frame Relay PVC.
Correct Answer: Global unicast
Correct Answer: Ping ::1
Explanation:
The loop back address with IPv4 is 127.0.0.1 . With IPv6, that address is ::1
Correct Answer: RADIUS Server
Correct Answer: The IEEE 80211i standard has been sanctioned by WPA and is termed WPA version 2
Correct Answer: PPPoE or PPPoA
Correct Answer: The loopback address written in dotted decimal and using three digits for each byte has a value of 135077009254 The system ID is 135077009254
Correct Answer: If a router has more than one route to the same IP prefix, the best path is the one with the highest LOCAL_PREF (assuming the WEIGHT attribute for the routes is equal)
Correct Answer: 255.255.254.0
Explanation:
Explanation: The requirement of having to allocate 500 hosts on each subnet can be achieved by the following: 2^9 = 512. So deducting the broadcast and network address we have 510 possible hosts on each subnet. We used 9 bits to allocate the hosts, this leaves us 7 bits for possible subnets. Those 7 bits in binary is 1111 1110 or 254 in decimal.
Correct Answer: /26
Explanation:
Explanation: 50 hosts require 6 bits of the last octet giving us 64 -2 = 62 possible hosts this satisfies our requirement and leaves us 2 bits over for the subnets. The default mask is /24 or 255.255.255.0 adding the 2 bits for the subnets it becomes 255.255.255.192 or /26
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