Which error are you likely to get when you run the following program? main() { struct emp { char name[20]; float sal; }; struct emp e[10]; int i; for ( i = 0 ; i <= 9; i++) scanf ( "%s %f" , e[i].name, &e[i].sal ); }

Correct Answer: The order may vary from compiler to compiler Here the multiplication will happen before the addition , but in which order the functions would be called is undefined In an arithmetic expression the parentheses tell the compiler which operands go with which operators but do not force the compiler to evaluate everything within the parentheses first

Correct Answer: Output may vary from compiler to compiler The order of evaluation of the arguments to a function call is unspecified

Correct Answer: 0 0 1 That's what some of the compilers would give But some other compiler may give a different answer The reason is, when a single expression causes the same object to be modified and then inspected the behaviour is undefined

Correct Answer: Constant expression required in the second case, we cannot use j

Correct Answer: The condition in the while loop is a must

Correct Answer: 4 8 10

Correct Answer: C++

Correct Answer: Add the following function prototype in main (): float f ( int, float );

Correct Answer: In spite of defining the function f() as returning void, the program is trying to collect the value returned by f() in the variable a

Correct Answer: Yes