Discussion
Home ‣ Technical Questions ‣ Programming Comments
- Question
What would be the output of the following program? main() { static int a[20]; int i = 0; a[i] = i++; printf ("\n%d%d%d", a[0], a[1], i); }
- Correct Answer
- 0 0 1 That's what some of the compilers would give But some other compiler may give a different answer The reason is, when a single expression causes the same object to be modified and then inspected the behaviour is undefined
- 1. Point out the error, if any, in the following program. main() { int i = 4, j = 2; switch(i) { case 1 : printf (''\n To err is human, to forgive is against company policy."); break; case j : printf (''\n if you have nothing to do, don't do it here."); break; } } Discuss
- 2. Point out the error, if any, in the while loop. main() { int i = 1; while () { printf ( "%d", i++); if (i >10) break ; } } Discuss
- 3. Point out the error, if any, in the following program. main() { int ( *p )() = fun; ( *P ) (); } fun () { Printf ( "\nLoud and clear" ); } Discuss
- 4. What is the difference between the following declarations? extern int fun(); int fun(); Discuss
- 5. What would be the output of the following program? main() { extern int i; i = 20; printf( "%d", sizeof(i) ); } Discuss
- 6. What would be the output of the following program? main() { int i=2 ; printf ("\n%d%d", ++i, ++i ); } Discuss
- 7. In the following code in which order the functions would be called? a = ( f1 ( 23,14 ) * f2 ( 12/4) ) + f3() ; Discuss
- 8. Which error are you likely to get when you run the following program? main() { struct emp { char name[20]; float sal; }; struct emp e[10]; int i; for ( i = 0 ; i <= 9; i++) scanf ( "%s %f" , e[i].name, &e[i].sal ); } Discuss
- 9. What would be the output of the following program? main() { printf (" %d%d%d ", sizeof (3.14f), sizeof (3.14), sizeof (3. 141); } Discuss
- 10. What would be the output of the following program? main() { float a = 0.7; if ( a < 0.7f ) printf ( " C "); else Printf ( " C++ "); } Discuss
Programming problems
Search Results
Correct Answer: Constant expression required in the second case, we cannot use j
Correct Answer: The condition in the while loop is a must
Correct Answer: Here we are initalising the function pointer p to the address of the function fun() But during this initialisation the function has not been defined Hence an error To eliminate this error add the prototype of the fun() before declaration of p, as shown below: extern int fun(); or simply int fun();
Correct Answer: There is no difference except for the fact that the first one gives a hint that the function fun() is probably in another source file
Correct Answer: extern int i is a declaration and not a definition, hence Error occured
Correct Answer: Output may vary from compiler to compiler The order of evaluation of the arguments to a function call is unspecified
Correct Answer: The order may vary from compiler to compiler Here the multiplication will happen before the addition , but in which order the functions would be called is undefined In an arithmetic expression the parentheses tell the compiler which operands go with which operators but do not force the compiler to evaluate everything within the parentheses first
Correct Answer: Floating point formats not linked
Correct Answer: 4 8 10
Correct Answer: C++
Comments
There are no comments.More in Technical Questions:
Programming
Copyright ©CuriousTab. All rights reserved.