What would be the output of the following program? # define SQR(x) (x * x) main() { int a, b = 3; a = SQR ( b + 2 ); Printf ("
%d ", a ); }

Question

What would be the output of the following program? # define SQR(x) (x * x) main() { int a, b = 3; a = SQR ( b + 2 ); Printf ("
 %d ", a ); }

Accepted Answer

11 Because, on preprocessing the expression becomes a = ( 3 + 2 * 2 + 3), as Ist preference is multiply & then addition, it evalvates as(3+ 2 * 3 +2) = (3+6+2)=11

What would be the output of the following program? # define SQR(x) (x * x) main() { int a, b = 3; a = SQR ( b + 2 ); Printf ("\n %d ", a ); }

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