public static void main string[] args Meaning is?

Correct Answer: Encryption

Explanation:

The coding or scrambling of data so that humans cannot read them is known as encryption.

Correct Answer: An explicit intent explicitly defines the activity the developer wishes to start Script code : Intent myIntent = new Intent(this, MyNewActivityclass); startActivity(myIntent);

Correct Answer: 100

Explanation:

Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs.The input program to compiler looks like this :

main ()

{

100;

printf("%d\n",100);

}

Note: 100; is an executable statement but with no action. So it doesn't give any problem.

Correct Answer: =

Explanation:

The valid escape codes in programming languages are ', ", \, n, or t are the valid escape codes. 

 

For example, the sequence \n usually represents a newline, while the escape sequence \\ represents a backslash, \t usually represents a newtab.

Correct Answer: H

Explanation:

* is a dereference operator & is a reference operator. They can be applied any number of times provided it is meaningful. Here p points to the first character in the string "Hello". *p dereferences it and so its value is H. Again & references it to an address and * dereferences it to the value H

main()

{

    float a = 5.375 ;

    char *p;

    int i;

    p = ( char* ) &a ;

    for ( i = 0; i <= 3 ; i++ )

          printf ( " %02x ", (unsigned char ) p[i] );

}

Correct Answer: 00 00 AC 40

Correct Answer: 0..1..2

Explanation:

enum assigns numbers starting from 0, if not explicitly defined.

Correct Answer: The Lord of the Rings

Correct Answer: Error occurs because we have mixed the ANSI prototype with K & R style of function definition When we use ANSI prototype for a function and pass a float to the function it is promoted to a double When the function accepts this double into a float a type mismatch occurs hence the error The remedy for this error could be to define the function as : int fun (float aa) { }

Correct Answer: Looping