What is the output of this program? #include using namespace std; struct sec { int a; char b; }; int main() { struct sec s ={25,50}; struct sec *ps =(struct sec *)&s; cout << ps->a << ps->b; return 0; }

Correct Answer: address of arr

Explanation:

As we couted to print only arr, it will print the address of the array.

Correct Answer: Structure: Initially (in C) a structure was used to bundle different type of data types together to perform a particular functionality But C++ extended the structure to contain functions also The major difference is that all declarations inside a structure are by default public Class: Class is a successor of Structure By default all the members inside the class are private

Correct Answer: The free subroutine frees a block of memory previously allocated by the malloc subroutine Undefined results occur if the Pointer parameter is not a valid pointer If the Pointer parameter is a null value, no action will occur The realloc subroutine changes the size of the block of memory pointed to by the Pointer parameter to the number of bytes specified by the Size parameter and returns a new pointer to the block The pointer specified by the Pointer parameter must have been created with the malloc, calloc, or realloc subroutines and not been deallocated with the free or realloc subroutines Undefined results occur if the Pointer parameter is not a valid pointer

Correct Answer: Multiple inheritance is a feature in C++ by which one class can be of different types Say class teaching Assistant is inherited from two classes say teacher and Student

Correct Answer: Early binding refers to the events that occur at compile time Early binding occurs when all information needed to call a function is known at compile time Examples of early binding include normal function calls, overloaded function calls, and overloaded operators The advantage of early binding is efficiency

Correct Answer: 10

Explanation:

In this program, we called by value so the value will not be changed, So the output is 10

Correct Answer: A function prototype is a declaration of a function that omits the function body It specifies the function?s name, argument types and return type Eg int add(int,int)

Correct Answer: The C++ programming technique allows defining user defined datatypes through structure The syntax to declare structure is as follows: struct student { char name[100] char address[250] };

Correct Answer: A reference variable provides an alias to a previously defined variable Data type & reference-name = variable name

Correct Answer: 2

Explanation:

There are two formats for initializers in C++ as shown in the example that follows. The first format uses the traditional C notation. The second format uses constructor notation.

int foo = 123;

 

int bar (123);