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- Question
What is friend function?
- Correct Answer
- The function declaration should be preceded by the keyword friendThe function definitions does not use either the keyword or the scope operator :: The functions that are declared with the keyword friend as friend functionThus, a friend function is an ordinary function or a member of another class
- 1. How variable declaration in c++ differs that in c? Discuss
- 2. Where is the reference stored?
Options- A. stack
- B. heap
- C. queue
- D. None Discuss
- 3. Default constructor accepts how many arguments?
Options- A. one
- B. two
- C. three
- D. None Discuss
- 4. What could be the bucket size if collision and overlapping occur at same time?
Options- A. 2
- B. 0
- C. 1
- D. 4 Discuss
- 5. What are the methods are available in storing sequential files?
Options- A. Natural merging
- B. Polyphase sort
- C. Distribution of Initial runs
- D. All the above Discuss
- 6. What is the output of this program? #include using namespace std; struct sec { int a; char b; }; int main() { struct sec s ={25,50}; struct sec *ps =(struct sec *)&s; cout << ps->a << ps->b; return 0; }
Options- A. 252
- B. 253
- C. 254
- D. 262 Discuss
- 7. What are the mandatory part to present in function pointers?
Options- A. &
- B. retrun values
- C. data types
- D. none of these Discuss
- 8. What is the output of this program ? #include using namespace std; int n(char, int); int (*p) (char, int) = n; int main() { (*p)('d', 9); p(10, 9); return 0; } int n(char c, int i) { cout << c << i; return 0; }
Options- A. d99
- B. d9d9
- C. d9
- D. compile time error Discuss
- 9. which keyword is used to define the macros in c++?
Options- A. macro
- B. define
- C. #define
- D. none of these Discuss
- 10. How many types of macros are there in c++?
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
Technology problems
Search Results
Correct Answer: C requires all the variables to be declared at the beginning of a scope but in c++ we can declare variables anywhere in the scope This makes the programmer easier to understand because the variables are declared in the context of their use
Correct Answer: stack
Explanation:
Referencee is stored in stack
Correct Answer: None
Explanation:
Default constructors has no arguments
Correct Answer: 1
Explanation:
One. If there is only one entry possible in the bucket, when the collision occurs, there is no way to accommodate the colliding value. This results in the overlapping of values
Correct Answer: All the above
Explanation:
ll the above listed methods are used in storing sequential files
Correct Answer: 252
Explanation:
In this program, We are dividing the values of a and b, printing it.
Correct Answer: data types
Explanation:
The data types are mandatory for declaring the variables in the function pointers.
Correct Answer: d99
Explanation:
In this program, we have declared the values as integer instead of character, So it is printing as d99 but it will not arise an error.
Correct Answer: #define
Correct Answer: 2
Explanation:
There are two types of macros. They are object-like and function-like.
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