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- Question
For a certain reaction,DGq = -45 kJ/mol and DHq= -90 kJ/mol at 0°C. What is the minimum temperature at which the reaction will become spontaneous, ifDHq and DSq are independent of temperature?
Options- A. 273 K
- B. 298 K
- C. 546 K
- D. 596 K
- Correct Answer
- 546 K
ExplanationT = 273 °K
Using the formula,
DGq = DHq ?TDS
-45 = -90 ?273 DS
DS = 0.164
Now since DHq and DSq are independent,T2= DH/DS = 45/0.164 = 273°K
Required Temp = 273 + 273 = 546°K
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