The reduction potential of hydrogen half-cell will be negative if : (1) PH2 = 2

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The reduction potential of hydrogen half-cell will be negative if : (1) PH2 = 2 atm and [H+] = 2.0 M (2) PH2 = 1 atm and [H+] = 2.0 M (3) PH2 = 1 atm and [H+] = 1.0 M (4) PH2 = 2 atm and [H+] = 1.0 M
Options
A. Option 1
B. Option 2
C. Option 3
D. Option 4

Correct Answer

Option 4

Explanation

$H^{+} - e^{-} ? \frac{1}{2} H_{2}$

Apply Nernst equation

$E = 0 - \frac{0.059}{1} \log (\frac{P H_{2}^{\frac{1}{2}}}{[H^{+}]})$

$E = - \frac{0.059}{1} \log (\frac{2^{\frac{1}{2}}}{1})$

Therefore E is Negative

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