Clearly, the given arrangement is as under :
In the first step, the first three and the last three letters are written in a reverse order.
Then, the first four and the last three letters are written in a reverse order.
The process is repeated to obtain successive output steps.
Third batch : soap shy miss pen yet the she
Second batch : pen miss shy soap she the yet
First batch : shy miss pen soap yet the she
1 |
2 |
2 |
5 |
8 |
15 |
9 |
20 |
9 |
20 |
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
∴ P(E) = | n(E) | = | 9 | . |
n(S) | 20 |
1 |
13 |
3 |
13 |
1 |
4 |
9 |
52 |
3 |
13 |
∴ P (getting a face card) = | 12 | = | 3 | . |
52 | 13 |
Efficiency (Asha : Usha) = 5 : 4
Number of days(Asha : Usha) = 4x : 5x = 4x : 25
? Number of days required by Asha to finish the work alone = 4x
= 4 x 5 = 20.
Now, since Asha and Usha did work together for last 5 days = 5 x 9 = 45%
(since efficiency of Asha = 5% and Usha's efficiency = 4%)
It means Asha completed 55% work alone.
? No. of days taken by Asha to complete 55% work = 55/5 = 11days
Efficiency of Kavita = 5%
Efficiency of Babita = 1.66%
Efficiency of Samita = 3.33%
Work done in 5 days by K + B + S = 5 x 10 = 50%
Work done in 3 days by K + B = 3 x 6.66 = 20%
Remaning work (30%) done by Kavita alone = 30/5 = 6 days
M1 = 250, D 1 = 33 days
per day meal W1 = W2 = 125 g
M2 = (250 + 80) =330 and D2=?
According to the formula
M1D1W2 = M2D2W1
250 x 33 x 125 = 330 x D2x 125
? D2 = (250 x 33)/330
? D2 = 25 days
Required average salary
= ( 6000 x 2 + 8000 x 3) / (2 + 3 )
= 36000 / 5
= Rs. 7200
Efficiency ( per minute) of Modi = 4 copies/min
Efficiency of Modi and Xerox together = 10 pages/min
? Efficiency of Xerox alone = 10 - 4 = 6 pages/min
? Mr. Xerox needs 6 min to copy 36 pages.
According to question,
A can run a distance of 1 Km in 3 minutes 10 seconds and B can run the same distance in 3 minutes 20 seconds.
A beats B by 10 sec.
So distance covered by B in 10 sec. = (1000 *10 / 200) m = 50 m
? A beat B by 50 m.
Required number of straight lines
=nC2 - mC2 + 1
Here, n = 10, m = 5
= 10C2 - 5C2 + 1
= 45 - 10 + 1 = 36
B's 4 days work = (1/6) x 4 = 2/3
? Remaining work = 1 - (2/3) = 1/3
A's 1 day's work = 1/10
? 1/3 work is finished by A in
(10 x 1/3) = 31/3 days
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