There are 10 digits. Now, third digit from the right means (10-3+1 = ) 8th digit from the left. But, from the question , third and eighth digits are interchanged. Hence, the required digit is the third digit of the given number, ie 0.
The possibe two-digit numbers are: 88, 85, 82, 81, 87, 86, 58, 28, 18, 78, 68
These are 11 in number
There are 26 English Alphabets. They are:
A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z.
Therefore, from the left end the 13th letter is M and is Consonent. And from the right end the 13th letter is N and is Consonent.
According to the question, after the position of the first and third digit interchanged new numbers are
789, 415, 856, 784, 404, 962
962, 856, 789, 784, 404, 415
Here the second lowest number is 404 and the last digit of it is '4'.
Number of boys in the row = number of boys uptil P + number of boys between P and Q + number of boys including Q and those behind Q = 14 + 4 + 7 = 25.
Total number of students in the class = 28 + 6 i.e, from top(7-1)
28 + 6 = 34
Only one such symbol is there in the given arrangement.
It is 4@5.
M is 8th from the top.
H is (50 - 20 + 1 =) 31 st from the top.
Number of students between M and H = (31 - 8- 1=)22
We have to find out even number - even number - odd number sequence.
8 5 8 6 7 6 8 9 3 2 7 5 3 4 2 2 3 5 5 2 2 8 1 1 9 3 1 7 5 1
There are four such such even numbers: 6,8,2 and 8.
The new number formed is 4 3 0 1 8 2 7 9 6 5
The seventh digit from the left is 7, the 3rd digit from the left of 7 is 1
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