and (44 + 28)/9 = 8
Therefore, (64 + 53)/9 = 13.
3 | 5 | 9 | 17 | 33 | 65 |
7 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (d)? |
The given series is in the below pattern ,
First series :-
First term = 3
Second term = First term × 2 - 1
? Second term = 3 × 2 - 1 = 5
Third term = Second term × 2 - 1
? Third term = 5 × 2 - 1 = 9
similarly , we can find the all others terms .
Second series :-
First term = 7
Second term = First term × 2 - 1
? Second term = 7 × 2 - 1 = 13
Third term = Second term × 2 - 1
? Third term = 13 × 2 - 1 = 25
Fourth term = Third term × 2 - 1
? Fourth term = 25 × 2 - 1 = 49
Fifth term = Fourth term × 2 - 1
? Fifth term = 49 × 2 - 1 = 97
Hence , the place value of ( d ) is 97 .
and (5)2 + (3)2 + (8)2 = 98
Therefore (6)2 + (7)2 + (3)2 = 94.
5 | 8 | 6 | 10 | 7 | 12 |
7 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (c)? |
The given series is in the below pattern ,
First series :-
First term = 5
Second term = First term × 2 - 2
? Second term = 5 × 2 - 2 = 8
Third term = Second term ÷ 2 + 2
? Third term = 8 ÷ 2 + 2 = 6
Fourth term = Third term × 2 - 2
? Fourth term = 6 × 2 - 2 = 10
similarly , we can find the all others terms .
........... and so on.
Second series :-
First term = 7
Second term = First term × 2 - 2
? Second term = 7 × 2 - 2 = 12
Third term = Second term ÷ 2 + 2
? Third term = 12 ÷ 2 + 2 = 8
Fourth term = Third term × 2 - 2
? Fourth term = 8 × 2 - 2 = 14
Hence , the place value of ( c ) is 14 .
and (5 x 4 - 5) = 15
(5 x 5 - 3) = 22.
2 | 3 | 6 | 15 | 45 | |
16 | (a) | (b) | (c) | (d) | (e) |
Which of the following numbers will come in place of (d)? |
As per the details in the question the series is in the form of
First series :-
First term = 2
Second term = First term × 1.5
? Second term = 2 × 1.5 = 3
Third term = Second term × 2
? Third term = 3 × 2 = 6
similarly , we can find the all others terms .
Second series :-
First term = 16
Second term = First term × 1.5
? Second term = 16 × 1.5 = 24
Third term = Second term × 2
? Third term = 24 × 2 = 48
Fourth term = Third term × 2.5
? Fourth term = 48 × 2.5 = 120
Fifth term = Fourth term × 3
? Fifth term = 120 × 3 = 360
Hence , the place value of ( d ) is 360 .
(6 + 9 + 5)/2 = 10
(3 + 7 + 2)/2 = 6.
The Given Series of alphabets
C E B A C D B C D A C E B E D C A B A D A C E D U B A U B D B U
After arranging the given series of alphabets in reverse order
U B D B U A B U D E C A D A B A C D E B E C A D C B D C A B E C
Method 1 to solve the question.
Now 7th position from left side
U B D B U A B U D E C A D A B A C D E B E C A D C B D C A B E C
Now 8th to the right of the alphabet B
U B D B U A B U D E C A D A B A C D E B E C A D C B D C A B E C
Method 2 to solve the question
Now, 8th to the right of the 7th from the left end = (8 + 7)th
i.e., 15th from the left end = B
U B D B U A B U D E C A D A B A C D E B E C A D C B D C A B E C
(7 x 6) + 2 = 44
(7 x 5) + 2 = 37.
5 - 4 = 1, 4 - 3 = 1 ? 1 + 1 = 2
6 - 0 = 6, 5 - 1 = 4, ? 6 + 4 = 10
6 - 2 = 4, 7 - 2 = 5 ? 4 + 5 = 9
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