This can be done in a method called Approximation.
Now,
Unit digit of this expression is always 1 as the base ends with 1.
For the tenth place digit we need to multiply the digit in the tenth place of the base and unit digit of the power and take its unit digit.
i.e, tenth place digit in 2151 is 5 and
tenth place digit in power 415 is 1
And the units digit in the product of 5 x 1 = 5
Therefore, last two digits of is 51.
The quadratic equation whose roots are reciprocal of can be obtained by replacing x by 1/x.
Hence, 2(1/x)(1/x)+ 5(1/x) + 3 = 0
=>
-4-(-10) = -4+10 = 6
-10-(-4) = -10+4= -6
Therefore, 6-(-6) = 6+6 = 12
Let the least value of the prize = Rs. x
Then the next value of the prize is x+30 , x+60, x+90, ....x+240.
Given total amount of cash prizes = Rs.1890
--> x + (x+30) + (x+60) + (x+90) + ....+ (x+240) = 1890
--> 9x + (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240) = 1890
--> 9x + 30(1 + 2 + 3 + 4....+ 8) = 1890
--> 9x + 30(36) = 1890
--> 9x = 810 --> x=90
Hence the least value of the prize x=90
Using BODMAS law,
3 x 3 + 3 - 3 + 3 =
3 x 3 = 12
= 12 + 3 - 3 + 3
= 9 + 3
= 12
Hence, 3 x 3 + 3 - 3 + 3 = 12.
? = 5068 x 4/37
? = 548
Given 7 + 7/7 + 7 x 7 - 7
By using BODMAS rule,
7 + 1 + 7 x 7 - 7
= 8 + 49 - 7
= 57 - 7
= 50.
Hence 7 + 7/7 + 7 x 7 - 7 = 50.
Given equation is
Here it is in the form of
Here m = 2.5 , n = p, m+n = 7
=> 2.5 + p = 7
=> p = 7 - 2.5
=> p = 4.5
Here the given expression,
is an algebraic expression. Here in this expression the terms are like terms. Now to add them, add their coefficients.
Here in the given expression, the like terms are two
Hence, adding their coefficients i.e, 1 + 1 = 2
Therefore,
= 2 .
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