We know that in A.P series
18th term = a + 17d
29th term = a + 28d
But given
a + 17d = 29..........(i)
a + 28d = 18......... (ii)
Solving equation (i) and (ii), we get
d = -1
put d = -1 in any of the above equations and we get,
a = 46
Now, we know 49th term can be written as, a + 48d
putting the value of a and d in the above equation,
a + 48d = 46 + 48(-1)
= 46 - 48
= -2
Hence, the 49th term is -2.
Fruits reduced by 1/4.
Total no. of bags N = 5
Formula to find no. of fruits in 1st bag = 4^n
Last Bag = 4 fruits.
That means, 4th bag = 4 x 4 = 16 fruits
3rd bag = 16 x 4 = 64 fruits
2nd bag = 64 x 4 = 256 fruits
1st bag = 256 x 4= 1024 fruits.
Let x be number of houses and y be colors.
on the basis of question
x = 4y+1
x = 5(y-1)
on solving these 2 equations x = 25
First ten odd numbers form an arithmetic progression of the form
1,3,5,7,9......
here a = first term = 1
d = common difference = 2
Average of first n numbers = (2a + (n - 1)d)/2
n th term of the AP = a + (n - 1)d
Substituting a = 1, d = 2 and n = 10 in the above formulas
average of first 10 numbers = 10
10 th term of the AP = 19
Therefore average of first 10 terms is 19 - 10 = 9 greater than
the last term. Hence the average is greater than the sum by
9/19 X 100 = 900/19 %
No. of students will be 98 x 12 = 1176
let us consider n circles then 1 + 2 + 3 + ....+ n = 1176
n(n+1)/2 = 1176
n = 48 circles.
If 'k' is number of students in P and 'l' is number of students in Q, then
From the given conditions, we have
=> k - 10 = l + 10 .......(1)
=> k + 20 = 2(l - 20) ....(2)
Solving these eqns, we get
k = 100 and l = 80.
Therefore, number of students in class Q is 80.
Two angles whose sum is 180 degrees are called supplementary angles.
Binary system is what the representation uses only two digits 0 & 1.
It uses only the powers of 2.
Here given formula is
and it is possible if and only if a = b = c.
From the trial and error method,
1) Let a = b = c = 1
Now substitute these values of a, b, c in the above formula.
We get 1 + 1 + 1 - 1 - 1 - 1 = 3 - 3 = 0
2) Now, let a = b = c = 4
Now substitute these values of a, b, c in the above formula.
We get 16 + 16 + 16 - 16 - 16 - 16 = 48 - 48 = 0.
Hence, it is possible that
We all know about BODMAS rule, by using that
3x3x3+3+3/3
= 3x3x3+3+1
= 27+3+1
= 27 + 4
= 31
Hence, 3x3x3+3+3/3 = 31.
Perimeter = 36
? 2 ( l + w ) = 36
? l + w = 18
Since length and width are positive integers in centimeters.
Therefore, possible dimensions are :
( 1, 17 )cm , ( 2, 16 ) cm , ( 3, 15 ) cm, (4 , 14) cm, ( 5,13) cm, ( 6, 12) cm , ( 7, 11) cm, ( 8, 10 ) cm, ( 9, 9) cm.
Hence, there are 9 rectangles.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.