Volume required in the tank = (200 x 150 x 2) cu.m = 60000 cu.m
Length of water column flown in1 min =(20 x 1000)/60 m =1000/3 m
Volume flown per minute = 1.5 x 1.25 x (1000/3) cu.m= 625 cu.m.
Required time = (60000/625)min = 96min
When N is a natural number, then there is only one possible case that N, N + 2, N + 4 are prime numbers.
When N = 3, then N, N + 2, N + 4 = 3, 5, 7 all are primes.
Let us assume the ratio product is Q.
According to question,
Quantity of Milk in mixture = 6Q ml
Quantity of Water in mixture = 2Q ml
Quantity of Milk in mixture + Quantity of Water in mixture = 640
6Q + 2Q = 640
8Q = 640
Q = 640/8
Q = 80
Quantity of Milk in mixture = 6Q ml = 6 x 80 = 480 ml
Quantity of Water in mixture = 2Q ml = 2 x 80 = 160 ml
To find the new mixture containing half milk and half water,
Quantity of water to be added for making the mixture of equal quantity of milk and water = 480 - 160 = 320
?DAC = ?B + ?C
(Exterior angle prop. of a ? ABC)
According to question,
130° = 2A + 3A
5A = 130°
A = 26°
? ?B = 52°; ?C = 78°
Total required marks in the three examinations = (3 x 600 x 70)/100 =1260
Marks secured in first examination = 55% of 600 = ( 600 x 55)/100 =330
Marks secured in second examination = 60% of 600 = ( 600 x 60)/100 =360
Thus, the required marks in third examination = 1260 - (330 + 360)
= 1260 - 690
= 570
Time taken by A to cover 400 m = Distance/ Speed
= 400/16 s = 25 s
? B covers (400 -16) = 384 m in(25 + 40) = 65 s
? B's speed = 384/65 =5.9 m/s
Probability of head or a tail on upper side of coin = 1/2
? Probability of getting same face on all three coins = 1/2 x 1/2 x 1/2
= 1/8
The distance covered by B in 35 seconds = 200 x 35 / 38 = 3500 / 19 m
Now, 200 ? 3500 / 19 = 300 / 19 = 1515?19 m Hence, A can beat B by 1515?19 m.
17 | 6 | km/hr |
7 |
Time taken = 1 hr 40 min 48 sec = 1 hr 40 | 4 | min = 1 | 51 | hrs = | 126 | hrs. |
5 | 75 | 75 |
Let the actual speed be x km/hr.
Then, | 5 | x x | 126 | = 42 |
7 | 75 |
⟹ x = | ❨ | 42 x 7 x 75 | ❩ | = 35 km/hr. |
5 x 126 |
63 |
487 |
119 |
993 |
125 |
999 |
125 |
999 |
0.125125... = 0.125 = | 125 |
999 |
5 | 1 |
4 |
13 | 1 |
2 |
Other side | = |
|
ft | ||||||||||||
= |
|
ft | |||||||||||||
= |
|
ft | |||||||||||||
= | 6 ft. |
∴ Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.
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