K's 1 day's salary = 1/10
L's 1 day's salary = 1/15
Together their 1 day's salary = 1/10 + 1/15
= 3/30 + 2/30
= 5/30
= 1/6
So the money will be enough for paying them both for 6 days.
Given that,
working days = 5
working hours = 8
A man get rupess per hour is Rs.2.40
So in one day the man get total rupees is 2.40 x 8 = 19.2
So in 5 days week the man get total rupees is 19.2 x 5 = 96
So in 4 week the man get total rupees is 96 x 4 = 384
So the man worked for = 160hours in 4 weeks
But given that the man earned Rs.432
Hence remaning money is (432-384 = 48)which is earn by doing overtime work
Overtime hours = 48/3.20 = 15
So total worked hours is = 15 + 160 = 175.
It is given that efficiency ratio =3:1
so time ratio will be 1:3 (since work is same)
Also given that time diff = 32 days. ratio difference = 3-1 =2
2 ratio = 32 days
1 ratio = 16 days.
So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days.
Total work = LCM of 16 and 48 = 48.
Total time = Total work/Total efficiency
ie; 48/4= 12 days.
In one day work done by K = 1/20
Work done by K in 2 days = 1/10
Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10
Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5
1/5th of the work will be completed at the end of 3 days.
The remaining work = 1 - 1/5 = 4/5
1/5 of work is completed in 3 days
Total work wiil be done in 3 x 5 = 15 days.
Given K=4L
-->K+L = 4L+L = 5L
These 5L people can complete the work in 24 days, which means L alone can do the work in (24 x 5)=120 days.
Hence, K alone can do the work in 120/4= 30 days.
Ratio of times taken by A and B = 160 : 100
A can do the work in 12 days
Let B can do the work in "D" days
=> 160:100 = 12 : D
=> D = 12 x 100/160 = 7.5 hrs
3/15 + 4/16 + x/24 = 1
Time taken to fill 2/7 = 1
Then to fill full 1 = ?
? = 1/(2/7) = 7/2 minutes.
Let M, N and O worked together for x days.
From the given data,
M alone worked for 8 days
M,N,O worked for x days
N, O worked for 1 day
But given that
M alone can complete the work in 18 days
N alone can complete the work in 36 days
O alone can complete the work in 54 days
The total work can be the LCM of 18, 6, 54 = 108 units
M's 1 day work = 108/18 = 6 units
N's 1 day work = 108/36 = 3 units
O's 1 day work = 108/54 = 2 units
Now, the equation is
8 x 6 + 11x + 5 x 1 = 108
48 + 11x + 5 = 108
11x = 103 - 48
11x = 55
x = 5 days.
Hence, all M,N and O together worked for 5 days.
Given for year = 70000
=> 365 days = 70000
=> 365 x 24 hours = 70000
=> 1 hour = ?
70000/365x24 = 7.990 = 8
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