From the given data,
12 children 16 days work,
One child?s one day work = 1/192.
8 adults 12 days work,
One adult?s one day?s work = 1/96.
Work done in 3 days = ((1/96) x 16 x 3) = 1/2
Remaining work = 1 ? 1/2 = 1/2
(6 adults+ 4 children)?s 1 day?s work = 6/96 + 4/192 = 1/12
1/12 work is done by them in 1 day.
1/2 work is done by them in 12 x (1/2) = 6 days.
We know that,
Here M1 = 1, D1 = 6 min, W1 = 1 and M2 = M, D2 = 90 min, W2 = 1845
=> M = 123
Let the number of days be 'p'
As the work is same, we know that
Where M = Men, D = Days, H = Hours per day
Here M1 = 9, D1 = 15, H1 = 7
M2 = 6, D2 = p, H2 = 9
=> 9 x 15 x 7 = 6 x p x 9
=> p = 35/2 = 17.5 days.
Let x liter be the per day filling and v litr be the capacity of the reservoir, then
90x + v = 40000 * 90 -----(1)
60x + v= 32000 * 60 ------(2)
solving eq.(1) and (2) , we get
x = 56000
Hence , 56000 liters per day can be used without the failure of supply.
Time taken by both Meghana and Ganesh to work together is given by =
Where
Therefore, time took by both to work together =
Let workdone 1 boy in 1 day be b
and that of 1 girl be g
From the given data,
4(5b + 3g) = 23
20b + 12g = 23 .......(a)
2(3b + 2g) = 7
6b + 4g = 7 ........(b)
Solving (a) & (b), we get
b = 1, g = 1/4
Let number og girls required be 'p'
6(7 x 1 + p x 1/4) = 45
=> p = 2.
Hence, number of girls required = 2
work done=total number of person x number of days;
half of work done = 140 x 66;
For half of remaining work 25 extra men are added.
Therefore, total men for half work remaining = 140 + 25 = 165;
Let 2nd half work will be completed in K days;
140 x 66 = 165 x K
K = 122;
Hence, extra days => 122-120 = 2days.
Given 2000 ---- 54 days
The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days.
i.e, 2000 ----- 39 days == m ---- 20 days
=> m x 20 = 2000 x 39
m = 3900
So total men for 20 days is 3900
=> 2000 old and 1900 new reinforcement.
Hence, reinforcement = 1900.
The mother completes the job in x hours.
So, the daughter will take 2x hours to complete the same job.
In an hour, the mother will complete 1/x of the total job.
In an hour, the daughter will complete 1/2x of the total job.
So, if the mother and daughter work together, in an hour they will complete 1/x + 1/2x of the job.
i.e., in an hour they will complete 3/2x of the job.
The question states that they complete the entire task in 6 hours if they work together.
i.e., they complete 1/6 th of the task in an hour.
Equating the two information, we get 3/2x = 1/6
By solving for x, we get 2x = 18 or x = 9.
The mother takes 9 hours to complete the job.
One day work of Raghu and Sam together = 1/12 + 1/15 = 9/60 = 3/20
Aru efficiency = 2/3 of (Raghu + Sam)
Number of days required for Aru to do thw work alone = 3/2 x 20/3 = 10 days.
B's 8 days work=(1/12) x 8 = 2/3
Reaining work= 1/3
Now, 1/15 work is done by A in 1 day
Therefore, 1/3 work is done by A in 15 x (1/3) = 5 days
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