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- Question
X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished?
Options- A. 1/3
- B. 2/3
- C. 1/6
- D. 5/6
- Correct Answer
- 1/6
ExplanationGiven X can do in 10 days
=> 1 day work of X = 1/10
Y can do in 15 days
=> 1 day work of Y = 1/15
1day work of (X + Y) = 1/10 + 1/15 = 1/6
Given they are hired for 5 days
=> 5 days work of (X + Y) = 5 x 1/6 = 5/6
Therefore, Unfinished work = 1 - 5/6 = 1/6
- 1. P can do a piece of work in 5 less days than Q. If both of them can do the same work in 1119 days, in how many days will Q alone do the same work ?
Options- A. 24 days
- B. 25 days
- C. 20 days
- D. 19 days Discuss
- 2. Time taken by P alone to finish a work is 50% more than the time taken by P and Q together. Q is thrice as efficient as R. If Q and R together can complete the work in 22.5 days, then how many days will P alone take to complete the work ?
Options- A. 17 days
- B. 11 days
- C. 15 days
- D. 16 days Discuss
- 3. A and B can do a piece of work for Rs 1540. Find the difference between the wages of C and B for the same work If A can do the work in 12 days and B can do the same work in 8 days and with the help of C, A and B can do the same work in 2 days?
Options- A. 980
- B. 1232
- C. 810
- D. 1121 Discuss
- 4. A can build a wall in 16 days while B can destroy it in 8 days. A worked for 5 days. Then B joined with A for the next 2 days. Find in how many days could A build the remaining wall ?
Options- A. 12 days
- B. 14 days
- C. 13 days
- D. 16 days Discuss
- 5. A contractor undertook a project to complete it in 20 days which needed 5 workers to work continuously for all the days estimated. But before the start of the work the client wanted to complete it earlier than the scheduled time, so the contractor calculated that he needed to increase 5 additional men every 2 days to complete the work in the time the client wanted it: If the work was further increased by 50% but the contractor continues to increase the 5 workers o every 2 days then how many more days are required over the initial time specified by the client.
Options- A. 1 day
- B. 2 days
- C. 5 days
- D. None of these Discuss
- 6. Three men, four women and six children can complete a work in 9 days. A women does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 9 days?
Options- A. 7
- B. 8
- C. 9
- D. 6 Discuss
- 7. A can complete 9/10 part of a work in 31 days. After that, with the help of B he can complete the remaining work in 4 days. In how many days will A and B together can complete that work ?
Options- A. 36
- B. 40
- C. 42
- D. 38 Discuss
- 8. Twenty men can do a work in eighteen days. Eighteen women can complete the same work in fifteen days. What is the ratio between the capacity of a woman and a man ?
Options- A. 4:5
- B. 3:4
- C. 4:3
- D. 2:3 Discuss
- 9. 16 men and 12 women can complete a work in 20 days. 18 women can complete the same work in 40 days. In how many days will 12 men 27 women complete the same work?
Options- A. 16 days
- B. 18 days
- C. 19 days
- D. 21 days Discuss
- 10. A tank has an inlet and outlet pipe. The inlet pipe fills the tank completely in 2 hours when the outlet pipe is plugged. The outlet pipe empties the tank completely in 6 hours when the inlet pipe is pluggeed. If there is a lekage also which is capable of draining out the liquid from the tank at half of the rate of outet pipe,them what is the time taken to fill the emty tank when both the pipes are opened?
Options- A. 3 hours
- B. 4 hours
- C. 5 hours
- D. None of these Discuss
Time and Work problems
Search Results
Correct Answer: 25 days
Explanation:
Let Q complete that work in 'L' days
=>
=>
L = 25 days.
Correct Answer: 15 days
Explanation:
We know that Time is inversely proportional to Efficiency
Here given time ratio of P & P+Q as
P/P+Q = 150/100 = 3:2
Efficiency ratio of P & Q as
P:Q = 2:1 ....(1)
Given Efficiency ratio of Q & R as
Q:R = 3:1 ....(2)
From (1) & (2), we get
P:Q:R = 6:3:1
P alone can finish the work in
22.5(3+1)/6 = 15 days.
Correct Answer: 1232
Explanation:
From the given data,
Day Capacity
A -> 12 2
B -> 8 3 2
A + B + C -> 2 12
=> Capacity of C = 12 - 5 = 7
Ratio of capacity of A : B : C = 2 : 3 : 7
Difference of wages of C & B = 4/5 x 1540
= 4 x 308 = Rs. 1232
Correct Answer: 13 days
Explanation:
Now, Total work = LCM(16, 8) = 48
A's one day work = + 48/16 = + 3
B's one day work = - 48/8 = -6
Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15
2days B joined with A in working = 2(3 - 6) = - 6
Remaining Work of building wall = 48 - (15 - 6) = 39
Now this remaining work will be done by A in = 39/3 = 13 days.
Correct Answer: 2 days
Explanation:
Total work = 100+50 = 150man-days
In 8 days 100 man-days work has been completed. Now on 9th and 10th day there will be 25 workers. So in 2 days they wll complete additional 50 man- days work. Thus the work requires 2 more days.
Correct Answer: 7
Explanation:
Given (3 Men + 4 Women + 6 Children) -----> 9 days
But W = 2M and C = M/2
Now, convert Men and Children into Women by
Therefore, 7 women alone can complete this work in 9 days.
Correct Answer: 40
Explanation:
Remaining work = 1 - 9/10 = 1/10
=> A & B together completes 1/10 of work in 4 days
=> 1 work can completed in ------ ? days
Let it be x days
=>
=> x = 40 days.
Hence, A & B together can complete the work in 40 days.
Correct Answer: 4:3
Explanation:
(20 x 18) men can complete the work in in one day.
one man's one day work = 1/360
(18 x 15) women can complete the work in 1 day
1 woman's one day work = 1/270
So, required ratio = = 4:3
Correct Answer: 16 days
Explanation:
(16M + 12W) x 20 = 18W x 40
=> 2M = 3W
Then,
Convert all men into women
12M + 27W = 27 + 12 x 3/2W = 45W
Let number of days required be 'D'
=> 18 x 40 = 45 x D
=> D = 16 days.
Correct Answer: 4 hours
Explanation:
Rate of leakage = 8.33% per hour
Net efficiency = 50 - (16.66 + 8.33)= 25%
Time required = 100/25 = 4 hours
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