Speed = = 2 m/sec = 2 x (18/5) km/hr = 7.2 km/hr
Total distance travelled in 12 hours =(35+37+39+.....upto 12 terms)
This is an A.P with first term, a=35, number of terms,
n= 12,d=2.
Required distance = 12/2[2 x 35+{12-1) x 2]
=6(70+23)
= 552 kms.
By investing Rs. 136, income obtained = Rs. 10.
By investing Rs. 6800, income obtained = = Rs. 500.
Income from Rs. 100 stock = Rs. 8.
Income from Rs. 2500 stock = = Rs. 200.
Cost of Rs. 100 stock = Rs. (100-15)
Cost of Rs. 6400 stock = = Rs. 5440.
For an income of Rs. 8, investment = Rs. 100.
For an income of Rs. 6, investment = = Rs. 75.
Market value of Rs. 100 stock = Rs. 75.
Relative speed of the thief and policeman = (11 ? 10) km/hr = 1 km/hr
Distance covered in 6 minutes = (1/60) x 6 km = 1/10 km = 100 m
Therefore, Distance between the thief and policeman = (200 ? 100) m = 100 m.
If the speed of the faster horse be and that of slower horse be then
and
Now, you can go through options.
The speed of slower horse is 20km/h
Since, 20+30=50
and
Speed = 9 km/hr = 9 x (5/18) m/sec = 5/2 m/sec
Distance = (35 x 4) m = 140 m.
Time taken = 140 x (2/5) sec= 56 sec
Time taken in walking both ways = 7 hours 45 minutes --------(i)
Time taken in walking one way and riding back= 6 hours 15 minutes-------(ii)
By equation (ii)*2 -(i), we have
Time taken to man ride both ways, = 12 hours 30 minutes - 7 hours 45 minutes
= 4 hours 45 minutes
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