∴(6767 + 1) will be divisible by (67 + 1)
∴(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
a2 + 1 = a
? a + 1/a = 1
On squaring both sides, we get
a2 + 1/a2 + 2 = 1
On cubing both sides, we get
(a2 + 1/a2)3 = (-1)3
? a6 + 1/a6 + 3a2 x 1/a2 (a2 + 1/a2) = -1
? a6 + 1/a6 + 3 x (-1) = -1
Now, a6 + 1/a6 + 1 = 3
As, a12 + a6 + 1 can be written as a6 + 1/a6 + 1
? a12 + a6 + 1 = 3
Solution 1 :
Let the number of ? 50 notes = x, then the number of ? 100 notes = (170 - x)
According to question.
50x + 100(170 - x) = 10000
divide by 50 the above equation, we will get
? x + 2(170 - x) = 200
? x + 340 - 2x = 200
? -x = 200 - 340 = -140
? x = 140
? Required amount ? 50 x 140
= ? 7000
Solution 2 :
Let the number of ? 50 notes = x and the number of ? 100 notes = y.
according to given question,
x + y = 170 .............(1)
50x + 100y = 10000............(2)
Divide the equation (2) by 10 , we will get
5x + 17y = 1000............(3)
Multiply the equation (1) by 5
5x + 5y = 850 ------------(4)
Subtract the (4) equation from (3) equation, we will get,
5x +10y - ( 5x + 5y ) = 1000 - 850
? 5x +10y - 5x - 5y = 1000 - 850
? 10y - 5y = 1000 - 850
? 5y = 150
? y = 150/5
? y = 30
Number of ? 100 notes = y = 30;
since x + Y = 170
therefore x = 170 - y
? x = 170 - 30
? x = 140
Number of ? 50 notes = x = 140
9 + | 3 | + 7 + | 2 | - | ❨ | 9 + | 1 | ❩ | =? |
4 | 17 | 15 |
Given sum |
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? a + 1/b = 1
ab + 1 = b ...(i)
Also, b + 1/c = 1
? b = 1 - 1/c ...(ii)
From Eqs. (i) and (ii), we get
ab + a = 1 - 1/c
? ab = -1/c
? abc = -1
Let the worker remains absent for x days.
Then, his working days = (120 - x) days.
According to the question,
20 x Working day - 3 x Absent day = 560
20(120 - x) - 3x = 560
? 2400 - 20x - 3x = 560
? x = 2400 - 560/23 = 1840/23
= 80 days
B runs 25 m in 5 seconds.
? B's time to cover 1 Km = 5 x 100 / 25 = 200 sec
A's time to cover one Km = 200 - 5 = 195 seconds
= 3 minutes 15 seconds.
3897 x 999 | = 3897 x (1000 - 1) |
= 3897 x 1000 - 3897 x 1 | |
= 3897000 - 3897 | |
= 3893103. |
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