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Home Aptitude Simplification Comments

  • Question
  • If 5x + 5 > 2 + 2x and 5x + 3 ? 4x + 5; then x can take which of the following values?


  • Options
  • A. 3
  • B. -2
  • C. -3
  • D. 1

  • Correct Answer


  • Tags: Bank Exams

    Simplification problems


    Search Results


    • 1. Which of the following is correct?

    • Options
    • A. (4x - 5y)2 = 16x2 - 20xy + 25y2
    • B. (4x - 5y)2 = 16x2 + 40xy - 25y2
    • C. (4x - 5y)2 = 16x2 - 40xy + 25y2
    • D. (4x - 5y)2 = 16x2 - 20xy - 25y2
    • Discuss
    • 2. If 1/(cosecA cotA) = x, then the value of x is

    • Options
    • A. cosecA + cotA
    • B. cosecA - cotA
    • C. cosec2A + cot2A
    • D. ?[cosec2A + cot2A]
    • Discuss
    • 3. If (tanA + tanB)/(1 tanAtanB) = x, then the value of x is

    • Options
    • A. tan(A + B)
    • B. tan(A - B)
    • C. cot(A + B)
    • D. cot(A - B)
    • Discuss
    • 4. If sin - 5?/3 = x, then the value of x is

    • Options
    • A. -?3/2
    • B. ?3/2
    • C. -2
    • D. -2/?3
    • Discuss
    • 5. What is the slope of the line perpendicular to the line passing through the points (8,2) and (3,1)?

    • Options
    • A. 5
    • B. 3/5
    • C. 5/3
    • D. 1/5
    • Discuss
    • 6. What is the value of sin 5?/3?

    • Options
    • A. ?3/2
    • B. 2/?3
    • C. 1/?3
    • D. -2/?3
    • Discuss
    • 7. cos3A is equal to

    • Options
    • A. cos3A - 3sin2cosA
    • B. cos3A + 4sin2cosA
    • C. cos3A + 3sin2cosA
    • D. cos3A - 4sin2cosA
    • Discuss
    • 8. 2 sec2A is equal to

    • Options
    • A. (1 - tanA)2 - (1 + tanA)2
    • B. ?[(1 - tanA)2 + (1 + tanA)2 ]
    • C. ?[(1 - tanA)2 - (1 + tanA)2]
    • D. (1 - tanA)2 + (1 + tanA)2
    • Discuss
    • 9. If 9x - [5(2x + 1)/2] = 9/2, then the value of x is?

    • Options
    • A. 7/4
    • B. -7/4
    • C. 4/7
    • D. -4/7
    • Discuss
    • 10. What is the equation of a line which has 3 as x-intercept and -5 as y-intercept?

    • Options
    • A. 3x - 5y = 15
    • B. 5x - 3y = 15
    • C. 5x + 3y = 15
    • D. 3x + 5y = 15
    • Discuss


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