In the below equation,
x2?15x + r = 0
sum of roots = p + q = -(-15)/1 = 15 (sum of roots for equation ax2+ bx + c is -b/a)
product of roots = pq = r/1 = r (product of roots for equation ax2+ bx + c is c/a)
given p ?q = 1
also we know that p+q = 15
subtracting the squares of both
(p+q)2 + (p-q)2 = 15^2?1
p2 + q2 + 2pq ?p2 ?q2 +2pq = 225 -1
4pq = 224
4r = 224
r = 56
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.