Mean of m observations is n
Mean of n-m observations is m
So total = nm+ (n-m)m
Total observations = n
Mean = Total / Total observations = (2mn-m^2)/n = 2m ?m^2/n
Let there be 2 circles with centre O1 and OAB is the common chord
Since both passes through the center of each other as shown in figure
So O1O is the radius of both
Let O1O = r = AO1= AO
AX = AB / 2 = 5?3 cm (since OX perpendicular to chord bisects it)
AOO1 forms an equilateral triangle with on side = radius = r
Sin 60 = ?3/2 = AX / AO = 5?3/r
So r = 10 cm
So diameter = 20 cm
In the below equation,
x2?15x + r = 0
sum of roots = p + q = -(-15)/1 = 15 (sum of roots for equation ax2+ bx + c is -b/a)
product of roots = pq = r/1 = r (product of roots for equation ax2+ bx + c is c/a)
given p ?q = 1
also we know that p+q = 15
subtracting the squares of both
(p+q)2 + (p-q)2 = 15^2?1
p2 + q2 + 2pq ?p2 ?q2 +2pq = 225 -1
4pq = 224
4r = 224
r = 56
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