To reach the winning post, A will have to cover a distance of (500 - 140). i.e, 360 m.
While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers 4 × 360 / 3 = 480 m.
So, A reaches the winning post while B remains 20 meter behind.
? A wins by 20 m.
Part filled by A in 1 h = 1/4
Part emptied by B in 1 h = 1/8
Part filled by (A + B) In 1 h = 1/4+ ( -1/8 ) = 1/4 - 1/8 = (2 - 1)/8 = 1/8
? Required time to fill the cistern = 8
Required answer = (12 x 16) /(12 + 16) = 48 / 7 = 66/7 minutes.
Work done by the inlet in 1 h = (1/8 - 1/24) = 1/24
Work done by the inlet in 1 min = 1/24 x 1/60 = 1/1440
? Volume of 1/1440 part = 3 L
? Volume of the whole = 3 x 1440 = 4320 L
4 | 1 | hours |
3 |
Work done by the leak in 1 hour = | ❨ | 1 | - | 3 | ❩ | = | 1 | . |
2 | 7 | 14 |
∴ Leak will empty the tank in 14 hrs.
Income of the deceased = Total income of 4 members - total income of remaining 3 members.
= 735 x 4 - 650 x 3 Rs.
= 990 Rs.
Area of the carpet = Area of the room
= 8 x 6 = 48 sq m
Width of the carpet = 75/100 = 3/4 m
Length of the carpet = 48 x (4/3)
= 16 x 4 = 64 m
? Cost of carpeting = 64 x 20 = ? 1280
Here, P1 : P2 : P3 = 2 : 3 : 5 [profit's ratio]
and x1 : x2 : x3 = 4 : 6 : 9 [investment's ratio]
According to the rule,
Required ratio = P1/x1 : P2/x2 : P3/x3
= 2/4 : 3/6 : 5/9
= 1/2 : 1/2 : 5/9 = 9 : 9 : 10
let the work done be 1 work.
Here M1=15, D1=16 W1=W2 =1
M2 =24 D2= ?
? According to the formula
M1 D1 W2 = M2 D2 W1
? 15 x 16 x 1 = 24 x D2 X 1
? D1 = 15 X 16/24 = 10
Therefore 10 days are required to complete the work
L?3 = M1/L = Surd of Lth order.
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