Let 36 is p% of 80
=> p x 80/100 = 36
=> p = 36 x 10/8 = 45.
Probability is Number of favourable outcomes by total outcomes
Total comes = 2 (Divisible or not)
Favourable = 1 (Divisible)
Hence, probability = 1/2.
56% of 870 = 56x870/100 = 487.20
82% of 180 = 82x180/100 = 147.60
32% of 90 = 32x90/100
487.20 + 147.6 - 28.8 = ?
? = 634.8 - 28.8
? = 606.
Here n(S) = 6 x 6 = 36
E={(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) ,(6,6),(1,3),(2,2),(2,6),(3,1),(3,5), (4,4),(5,3),(6,2)}
=> n(E)=20
Required Probability n(P) = n(E)/n(S) = 20/36 = 5/9.
Given the price of a commodity is decreased by p = 20%
And its consumption is increased by q = 10%
Now, required increase or decrease in the expenditure on the commodity can be
p + q + pq/100 = -20 + 10 - 200/100 = -10 - 2 = -12%.
Hence, decrease in the expenditure = 12%
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