Relative speed = (120 + 80) km/hr
=(200*5/18)m/s = (500/9)m/s
Let the length of the other train be x metres.
Then, x+270/9 = 500/9
=> x + 270 = 500
=> x = 230.
- 7 = 14
Given speed of the first train = 60 km/hr = 60 x 5/18 = 50/3 m/s
Let the speed of the second train = x m/s
Then, the difference in the speed is given by
=> x = 10 m/s
=> 10 x 18/5 = 36 km/hr
Second is obtained from the first.
n(E) = 5C3 + 4C3 + 3C3 = 10 + 4 + 1 = 15n(S) = 12C3 = 220
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